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sergeinik [125]
3 years ago
11

if a plane leave the ski resort every hour. the first plane leaves at 10 and the second plane leaves at 4 how man planes leave e

ach day
Mathematics
1 answer:
Butoxors [25]3 years ago
7 0
Asked and answered elsewhere.
brainly.com/question/9934382
You might be interested in
A coin weighs 4/15 ounces. A different coin weighs 1/15 ounces. How much do the two coins weigh together? Write your answer as a
olchik [2.2K]

Answer:

1/3

Step-by-step explanation:

4/15 + 1/15 = 5/15

simplified its 1/3

7 0
3 years ago
Enter your answer and show all the steps that you use to solve this problem in the space provided
VashaNatasha [74]

Answer: x = -4, x = 5

Step-by-step explanation:

You can use the substitution method for this problem.

y = x^{2} + 2x, but y also = 3x +20.

Because of this, you can determine that x^{2} +2x = 3x + 20 because they are both equal to the same thing, y.

Solve the quadratic equation you got from substitution:

x^{2} + 2x = 3x + 20

x^{2} -x = 20

x^{2} -x -20 = 0

You can factor this equation:

(x+4)(x-5) = 0

x = -4, x = 5

5 0
3 years ago
How do i solve for equations that have 2 variables
sergey [27]

Answer:

To solve for an equation with two variables, substitute a zero(0) into the other variable and find one variable.

Step-by-step explanation:

To solve for an equation with two variables, substitute a zero(0) into the other variable and find one variable.

Simple Example:

3x+3y=12

Substitute 0 as y,

3x+0=12

3x=12

12/3=4

x=4

Now substitute 4 into the main equation,

3(4)+3y=12

12+3y=12

-12      -12

3y=0

0/3=0

y=0

So the answer is

3(4)+3(0)=12

12=12

8 0
4 years ago
Which values are solutions? check all that apply PLEASE
alex41 [277]
A
B
F
 are all correct

I need to write more to get this published

6 0
4 years ago
Suppose we want to assess the effect of a one-day SAT prep class at a 5% level of significance. Scores on the SAT writing exam c
Dafna1 [17]

Answer:

The right answer is:

"The one-day SAT prep class produces statistically significant improvements in SAT writing performance."

Step-by-step explanation:

The P-value gives us the probability of getting the sample results, given that the null hypopthesis is true. That is why, it the P-value is small enough (smaller than the level of significance) is an indicator that the null hypothesis may not be true.

In this case, the P-value (0.028) is smaller than the level of significance (0.05), so the null hypothesis is rejected and we can conclude that there is significant difference for the studentes that take the SAT prep-class.

The population only include the students that take teh SAT prep-class, so it is not useful to compare to the performance of students that didn't take the class.

The right answer is:

"The one-day SAT prep class produces statistically significant improvements in SAT writing performance."

8 0
3 years ago
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