Ask question

Ask question

All categories

sergeinik [125]

3 years ago

11

if a plane leave the ski resort every hour. the first plane leaves at 10 and the second plane leaves at 4 how man planes leave e

ach day

1 answer:

Butoxors [25]3 years ago

7 0

Asked and answered elsewhere.
brainly.com/question/9934382

You might be interested in

HELP PLEASE WILL GIVE BRAINLIEST WORTH 50 POINTS

Alja [10]

Answer:

y = 8.13 x -16125.713

hope it helps

Step-by-step explanation:

Sum of X = 14004

Sum of Y = 977

Mean X = 2000.5714

Mean Y = 139.5714

Sum of squares (SSX) = 53.7143

Sum of products (SP) = 436.7143

Regression Equation = ŷ = bX + a

b = SP/SSX = 436.71/53.71 = 8.13032

a = MY - bMX = 139.57 - (8.13*2000.57) = -16125.71277

ŷ = 8.13032X - 16125.71277

8 0

3 years ago

Read 2 more answers

Just 16 not the words below

alekssr [168]

Answer:

Table F

Step-by-step explanation:

The equation is C = 0.75t. The variable c is for cost and t is for tickets. When we use substitution to solve the equation, we see that table F correctly represents the situation. In simpler terms, the equation is asking us to mutliply the cost PER ticket by the number of tickets.

0.75 * 1 = 0.75

0.75 * 2 = 1.50

0.75 * 3 = 2.25

0.75 * 4 = 3

And so on. As we can see, the only table that shows these values is in fact table F.

Hope this helps!

8 0

3 years ago

A hot tub is draining, and the water level is decreasing at a constant rate. After 9.3 minutes, the tub contains 401.92 gallons.

Darya [45]

Answer:

it's A y-intercept hope it helps

3 0

2 years ago

A triangle ABC has its vertices at A(-2, -3), B(2, 1), and C(5,-1).

maksim [4K]

$~\hfill \stackrel{\textit{\large distance between 2 points}}{d = \sqrt{( x_2- x_1)^2 + ( y_2- y_1)^2}}~\hfill ~ \\\\[-0.35em] ~\dotfill\\\\ A(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-3})\qquad B(\stackrel{x_2}{2}~,~\stackrel{y_2}{1}) ~\hfill AB=\sqrt{( 2- (-2))^2 + ( 1- (-3))^2} \\\\\\ AB=\sqrt{(2+2)^2+(1+3)^2}\implies AB=\sqrt{32}\implies \boxed{AB=4\sqrt{2}} \\\\[-0.35em] ~\dotfill$

$B(\stackrel{x_1}{2}~,~\stackrel{y_1}{1})\qquad C(\stackrel{x_2}{5}~,~\stackrel{y_2}{-1}) ~\hfill BC=\sqrt{( 5- 2)^2 + ( -1- 1)^2} \\\\\\ BC=\sqrt{3^2+(-2)^2}\implies BC=\sqrt{9+4}\implies \boxed{BC=\sqrt{13}} \\\\[-0.35em] ~\dotfill\\\\ C(\stackrel{x_1}{5}~,~\stackrel{y_1}{-1})\qquad A(\stackrel{x_2}{-2}~,~\stackrel{y_2}{-3}) ~\hfill CA=\sqrt{( -2- 5)^2 + ( -3- (-1))^2} \\\\\\ CA=\sqrt{(-7)^2+(-3+1)^2}\implies CA=\sqrt{49+(-2)^2}\implies \boxed{CA=\sqrt{53}}$

$\stackrel{\textit{\large perimeter of ABC}}{4\sqrt{2}+\sqrt{13}+\sqrt{53}~~\approx~~ 16.54}$

3 0

2 years ago

What is the volume of the cylinder below? Use 3.14 for x and round to the nearest tenth.

sdas [7]

The last one 1,459.3

8 0

3 years ago