Suppose R = {1,3,5,7,9,11,13,15,17} and D={3,6,9,12,15,18,21,24,27} r d
Free_Kalibri [48]
The intersection of sets R and D is give by the following set:
R ∩ D = {3, 9, 15}.
<h3>What is the missing information?</h3>
This problem is incomplete, but researching it on a search engine, we find that it asks the intersection of sets R and D.
<h3>What is the set that is the intersection of two sets?</h3>
The set that is the intersection of two sets is composed by the elements that belong to both sets.
For this problem, the sets are given as follows:
- R = {1,3,5,7,9,11,13,15,17}.
- D={3,6,9,12,15,18,21,24,27}
Hence the intersection is given by:
R ∩ D = {3, 9, 15}.
As the elements 3, 9 and 15 are the only ones that belong to both sets.
More can be learned about intersection of sets at brainly.com/question/11439924
#SPJ1
I think it’s 3 that’s what I got
The answer to your problem is........... 60..... i think :)
Answer:
D) (x+6, y+5)
Step-by-step explanation:
You can start with the top corner of triangle A
Then count up 5 units and right 6 units
Because you count vertically 5 units that means you're using the y-axis, And because you're counting up, than means the values are positive.
And because you count horizontally 6 units you're using the x-axis, And you are counting to the right so the values are positive.
Down vertically=Negative Y-axis Values. Up vertically=Positive Y-axis Values
Right horizontally=Positive X-axis values. Left horizontally=Negative X-axis Values
So 16=heads
18=tails
after you add some tails
18+x
ratio of heads to tails is 1:1.5
heads=16, didn't change
tails=18+x
so
1:1.5=16:18+x
fractionify
1/1.5=16/(18+x)
1/1.5=2/3
2/3=16/(18+x)
mutiply both sides by (3)(18+x)
2(18+x)=3(16)
36+2x=48
subtract 36 from both sides
2x=12
divide 2
x=6
6 tails added
total=heads+tails
heads=16
tails=18+6=24
total=16+24
total=40
6 tails added
40 total coins
