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Nina [5.8K]
3 years ago
11

What is the total area of this composite figure rounded to the nearest hundredth?

Mathematics
1 answer:
weqwewe [10]3 years ago
7 0

Answer:

choice #4, total=31.14 mm^2

Step-by-step explanation:

14x2=28 is area of rectangle

1^2xPi=area of small circle

3.14=area of small circle

total=31.14 mm^2

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Find the mean of first five prime<br> numbers​
gtnhenbr [62]

Answer:

5.6

Step-by-step explanation:

(2+3+5+7+11)/5

=5.6

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3 years ago
Graph the linear equation. Find three
Karo-lina-s [1.5K]
-3y = -2x -6

Y= 2/3x + 2


When x= 3
Y= 2/3(3) + 2
Y= 2+2 = 4

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When x= 6
Y=2/3(6)+2
Y= 4+2 = 6

(6,6)


When x= 12
Y= 2/3(12) + 2
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4 0
3 years ago
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lora16 [44]
The rule associated with moving decimal places, and multiplying by a value or multiple of 10, would be the following :

If you divide a value by 10 or a multiple of 10, you would move the decimal place to the left number of times as there are zeros in the multiple.

(Assuming that there are no zeros in the numerator value)

If you multiply by 10 multiple, then you would move the decimal to the right that many times as there are 0's in the value.

The solution would be that the decimal number is multiplied by 100.
4 0
3 years ago
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According to postal regulations, a carton is classified as "oversized" if the sum of its height and girth (the perimeter of its
sergij07 [2.7K]

Answer:

Square base dimension = 15 inches

Maximum volume = 7200 inches^3

Step-by-step explanation:

V = x^2y ..... eq 1

Let the square base be x and the height y

Oversize formular is given by

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Y= 92 - 4x .....eq 2

Put eq 2 into eq 1

V = x^2 ( 92 - 4x^3)

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Using derivatives

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X(184 -12x)

X=0

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Maximum Volume = V= 92(15)^2 -5(15)^3

V= 92(225) - 4(3475)

V= 20700 - 13500

V= 7200 inches^3

7 0
4 years ago
4. Four systems of equations are shown in the table. Indicate whether each system has no solution, one
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Answer:

Bbhhggggggg is the only one of those who have a great relationship with their

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