Answer:
![P =90\times 10^7\ W](https://tex.z-dn.net/?f=P%20%3D90%5Ctimes%2010%5E7%5C%20W)
Explanation:
Given that
Volume flow rate ,Q= 1200 m³ each seconds
So we can say that
Q= 1200 m³ /s
From energy conservation
(Potential energy +kinetic energy ) at top = (Potential energy +kinetic energy ) at bottom
U₁+ KE₁ = U₂+ KE₂
ρ Q g h + 0 = 0 + KE₂
KE₂= ρ Q g h
For water ,ρ = 1000 kg/m³
KE₂=1000 x 1200 x 10 x 100 W ( take g= 10 m/s²)
KE₂=120 x 10⁷ W
Only three forth of the energy converted into electrical energy
Therefore power P
![P=\dfrac{3}{4}\times KE_2](https://tex.z-dn.net/?f=P%3D%5Cdfrac%7B3%7D%7B4%7D%5Ctimes%20KE_2)
![P=\dfrac{3}{4}\times 120\times 10^7\ W](https://tex.z-dn.net/?f=P%3D%5Cdfrac%7B3%7D%7B4%7D%5Ctimes%20120%5Ctimes%2010%5E7%5C%20W)
![P =90\times 10^7\ W](https://tex.z-dn.net/?f=P%20%3D90%5Ctimes%2010%5E7%5C%20W)
Answer:
k = 52.2 N / m
Explanation:
For this exercise we are going to use the conservation of mechanical energy.
Starting point. When it is 30 m high
Em₀ = K + U = ½ m v² + m g h
Final point. Right when you hit the water
= K_{e} = ½ k x²
in this case the distance the bungee is stretched is 30 m
x = h
as they indicate that there are no losses, energy is conserved
Em₀ = Em_{f}
½ m v² + m g h = ½ k h²
k = ![\frac{m (v^{2} + 2 g h)}{h^{2} }](https://tex.z-dn.net/?f=%5Cfrac%7Bm%20%28v%5E%7B2%7D%20%2B%202%20g%20h%29%7D%7Bh%5E%7B2%7D%20%7D)
let's calculate
k =
k = 52.2 N / m
Answer:
C. All muscle contractions after Sarah reaches fatigue (about an hour into her run)
Explanation:
At the start of the marathon race, the main source of Sarah's energy will be the Adenosine Triphosphate (ATP) that her muscle has stored. After the exhaustion of the ATP stored, which averagely will be about an hour into the race, the creatine phosphate (which will be converted to ATP) will be her major energy source. But due to the non functionality of the creatine phosphate that she produces, there will be muscle contractions which will affect her race. Therefore, Sarah will suffer muscle contractions after she reaches fatigue( about an hour into her run)
Answer:
3.78 m on the left side of the seesaw
Explanation:
The net torque in this situation is zero, so the torque from each side of the pivot point must balance each other out:
(50.0 kg x 10.0 m/s^2)(3.4m) = (450 N) r
Solve for r, and you get 3.78 on the left side.
Hope this helps!