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Virty [35]
3 years ago
7

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Physics
2 answers:
Kitty [74]3 years ago
7 0

Answer:

AWESOME aren't we on the app right now

Explanation:

brilliants [131]3 years ago
5 0

Answer:

ok ty

Explanation:

You might be interested in
Does the air exert a buoyant force on all objects in air or only on objects such as balloons that are very light for their size?
Citrus2011 [14]

Answer:

See explanation

Explanation:

Solution:-

Buoyancy is the force that causes objects to float. It is the force exerted on an object that is partly or wholly immersed in a fluid. Buoyancy is caused by the differences in pressure acting on opposite sides of an object immersed in a static fluid. It is also known as the buoyant force. Buoyancy is the phenomena due to Buoyant Force.

It is as an upward force exerted by a fluid that opposes the weight of an object immersed in a fluid. As we know, the pressure in a fluid column increases with depth. Thus, the pressure at the bottom of an object submerged in the fluid is greater than that at the top. The difference in this pressure results in a net upward force on the object which we define as buoyancy.

- The formula for buoyant force (Fb) is given:

                           Fb = ρ*g*V

- The force acts on all objects. However, it depends on the fluid density and amount of volume displaced.

- The Buoyant force exerted by air with density = 1.225 kg/m^3 on an object with volume (V) is:

                          Fb = ρ*g*V = 1.225*9.81*V = 12.02*V

- For the similar object with mass (m), the downward weight would be:

                           W = m*g

- For the object to float the buoyant force (Fb) must be greater than weight of the object:

                          Fb > W

                          12.02*V > m*9.81

                          V / m > 0.816

- The ratio of V / m must be at-least = 0.816.

- Assuming the object is fully immersed in air, then the volume displaced V = ρ_material*V

                         ρ_material < 1 / 0.816

                        ρ_material < 1.225 or ( ρ_air )

- So the for an object to float in air its material density must always be less than that of air. That why in balloons lighter gas is used which have density less than that of air like Helium.          

4 0
3 years ago
A basketball player of height 2.40 m is standing 2.60 m in front of a convex spherical mirror of radius of curvature 4.00 m. Det
IrinaVladis [17]

Answer:

The size of the image is 1.04 m.

Explanation:

Given that,

Height of object = 2.40 m

Distance of object = 2.60 m

Radius of curvature =4.00 m

Focal length f=\dfrac{R}{2}=\dfrac{4.00}{2}=2.00

We need to calculate the image distance

Using mirror formula

\dfrac{1}{f}=\dfrac{1}{v}+\dfrac{1}{u}

\dfrac{1}{v}=\dfrac{1}{2.00}+\dfrac{1}{2.60}

\dfrac{1}{v}= \dfrac{23}{26}

v=1.13\ cm

We need to calculate the height of the image

Using formula of magnification

m=\dfrac{h'}{h}=-\dfrac{v}{u}

Put the value into the formula

\dfrac{h'}{2.40}=-\dfrac{1.13}{-2.60}

h'=\dfrac{1.13}{2.60}\times2.40

h'=1.04\ m

Hence, The size of the image is 1.04 m

8 0
3 years ago
What is F = m x a in Newton's laws of motion?
madam [21]

Answer:

This is Newton's second law.

<u>Newton's second law text:</u>

(If a resultant force acts on a body, then an acceleration will give it an acceleration, the magnitude of which is directly proportional to the amount of the net force, and a direction is in the direction of the net force itself)

F=ma

net force = mass x acceleration

I hope I helped you^_^

8 0
2 years ago
A 2 feet piece of wire is cut into two pieces and once a piece is bent into a square and the other is bent into an equilateral t
SpyIntel [72]

Answer:

Explanation:

Let x ft be used to make square and 2-x ft be used to make equilateral triangle.

each side of square = x/4

area of square = ( x /4 )²

Each side of triangle

= (2-x) /3

Area of triangle = 1/2 (2-x)²/9 sin 60

= √3 / 36 x (2-x)²

Total area

A = ( x /4 )² +√3 / 36 (2-x)²

For maximum area

dA/dx = 0

1/16( 2x ) -√3 / 36 x2(2-x) = 0

x / 8 - √3(2-x)/ 18 = 0

x / 8 - √3/9 + √3/18 x = 0

x ( 1/8 + √3/18 ) = √3/9

x(.125 +.096 ) = .192

x = .868 ft

3 0
2 years ago
To practice Problem-Solving Strategy 8.1 for circular-motion problems. A cyclist competes in a one-lap race around a flat, circu
Anna007 [38]

Answer:

Explanation:

distance travelled

s = 2πR

= 2 X 3.14 X 140

= 880 m

final velocity = v

initial velocity = u

distance travelled = s

time = 60 s

s = ut + 1/2 at²

880 = .5 x a x 60²

a = .244 m/s²

final velocity v = at

= .244 x 60

= 14.66

centripetal acceleration at final moment

v² /R

14.66 X 14.66 / 140

= 1.53 m/s⁻²

1.53 m/s²

this is centripetal acceleration which acts towards the centre.

tangential acceleration calculated a _t = .244

redial acceleration ( centripetal ) = 1.53

Resultant acceleration

R²= 1.53² + .244 ²

R = 1.55 m/s²

total force = 1.55 x 76

= 118 N  

5 0
3 years ago
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