ribosomes
an animal cell with a nucleus
animal
Answer:
Second drop: 1.04 m
First drop: 1.66 m
Explanation:
Assuming the droplets are not affected by aerodynamic drag.
They are in free fall, affected only by gravity.
I set a frame of reference with the origin at the nozzle and the positive X axis pointing down.
We can use the equation for position under constant acceleration.
X(t) = x0 + v0 * t + 1/2 * a *t^2
x0 = 0
a = 9.81 m/s^2
v0 = 0
Then:
X(t) = 4.9 * t^2
The drop will hit the floor when X(t) = 1.9
1.9 = 4.9 * t^2
t^2 = 1.9 / 4.9
That is the moment when the 4th drop begins falling.
Assuming they fall at constant interval,
Δt = 0.62 / 3 = 0.2 s (approximately)
The second drop will be at:
X2(0.62) = 4.9 * (0.62 - 1*0.2)^2 = 0.86 m
And the third at:
X3(0.62) = 4.9 * (0.62 - 2*0.2)^2 = 0.24 m
The positions are:
1.9 - 0.86 = 1.04 m
1.9 - 0.24 = 1.66 m
above the floor
Average velocity is a vector unit (i.e. includes magnitude <em>and </em>direction) calculated by working out distance ÷ time:
80 metres ÷ 20 seconds = 4 metres/seconds (m/s)
Therefore, your final answer is C. 4 m/s south.
The resulting expression for the product of 1.58 and 0.03 is 0.05
The resulting expression for the sum of 1.4 and 2.53 is 3.9
The resulting expression for the sum of 2.34 x 10² and 4.93 is 2.39 x 10²
Given the following expression
(a) 1.58 x 0.03
taking the product
Converting too 1 significant figure
b) 1.4 + 2.53
1.4 = 14/10
2.53 = 253/100
Find their sum
c) 2.34 x 10² + 4.93
Given that
4.93 = 4.93 × 10⁰
Hence;
Learn more about significant figures here:
brainly.com/question/17903415
In practice, something that follows a very predictable pattern can be used as a time standard. This include things like radioactive decay, planetary orbit, and the speed of light, among others.