All categories

3 years ago

A girl of mass 50.0 kg sits on the right-hand side of a seesaw at a distance of 3.4 m

Physics

1 answer:

deff fn [24]3 years ago

8 0

Answer:

3.78 m on the left side of the seesaw

Explanation:

The net torque in this situation is zero, so the torque from each side of the pivot point must balance each other out:

(50.0 kg x 10.0 m/s^2)(3.4m) = (450 N) r

Solve for r, and you get 3.78 on the left side.

Hope this helps!

You might be interested in

Reimbursement means that a client is A. able to apply for healthcare insurance and refunded for a partial sum of the payment pla

PSYCHO15rus [73]

Answer:

<u>Option-(C):</u> Refunded by an insurance company for costs incurred according to an agreement drawn up

Explanation:

<u>Reimbursement:</u>

There are certain institutes or insurance company, which holds the capacity to refund any cost or fee spent by its client. As the client will paid the due amount as per an agreement done before and as both the parties have agreed upon those terms prior to the situation faced.

5 0

4 years ago

?/1 Jorge traveled 5 miles north to school. He then traveled 3 miles west to the store. Then he left the store and traveled 5 mi

aleksklad [387]

Answer:

He's 3 miles west of school.

Explanation:

He went 5 miles up and 5 miles down which means that he really didn't go up or down. In between that, he went 3 miles west so if the 5 milers don't count, this puts him at 3 miles west of school.

4 0

3 years ago

A light ray in glass (n=1.5) hits the air-glass interface at an angle of 10 degrees from the normal. What angle from the normal

jekas [21]

Answer:

The angle from the normal is 15.1°.

Explanation:

We can find the angle by using Snell's law:

$n_{1}sin(\theta_{1}) = n_{2}sin(\theta_{2})$

Where:

n₁: is the first medium (glass) = 1.5

n₂: is the second medium (air) = 1.0

θ₁: is the first angle (in the glass) = 10°

θ₂: is the second angle (in the air) =?

$\theta_{2} = arcsin(\frac{n_{1}sin(\theta_{1})}{n_{2}}) = arcsin(\frac{1.5*sin(10)}{1.0}) = 15.1 ^{\circ}$

Therefore, the angle from the normal is 15.1°.

I hope it helps you!

7 0

3 years ago

An object moves 20 m east in 30 s and then returns to its starting point taking an additional 50 s. If west is chosen as the pos

disa [49]

The sign associated with the average velocity of the object is negative.

<h3>Average velocity of the object</h3>

The average velocity of the object is calculated as follows;

Average velocity = (v1 + v2)/2

v1 = -20/30 = -0.667 m/s

v2 = 20/50 = 0.4 m/s

Average velocity = (-0.667 + 0.4)/2

Average velocity = -0.134 m/s

Thus, the sign associated with the average velocity of the object is negative.

Learn more about average velocity here: brainly.com/question/6504879

#SPJ1

7 0

2 years ago

The electron gun in an old TV picture tube accelerates electrons between two parallel plates 1.0 cm apart with a 20 kV potential

Julli [10]

Answer:

A) electric field strength between the plates;E = 2 x 10^(6) N/C

B) exit velocity;v = 8.39 x 10^(7) m/s

Explanation:

We are given;

Potential difference; V = 20 kV = 20000 V

Distance between the 2 parallel plates; d = 1cm = 0.01 m

A) The electric field strength will be gotten from;

E = V/d

E = 20000/0.01

E = 2000000

E = 2 x 10^(6) N/C

B) For exit speed, we'll use the formula for Kinetic energy; KE = (1/2)mv²

KE is also expressed as; V•q_e

Thus,

(1/2)mv² = V•q_e

Where;

V is potential difference = 20000 V

Q_e is charge of electron which has a constant value of; (1.6 x 10^(-19))C

m is mass of electron with a constant value of (9.1 x 10^(-31)) kg

v is the velocity

Thus, making v the subject, we have;

v = √((2V•q_e)/m)

v = √((2 x 20000•(1.6 x 10^(-19)))/(9.1 x 10^(-31)))

v = 83862786 m/s or

v = 8.39 x 10^(7) m/s

3 0

3 years ago