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emmainna [20.7K]

3 years ago

7

O suma de bani a fost cheltuita astfel : In prima zi 10 la suta din suma In a 2-a zi 30 la suta din rest si au mai ramas 40 lei

. Aflati suma initiala . [ probleme cu procente ]

1 answer:

Shtirlitz [24]3 years ago

8 0

For All Who Speak English

<span>A sum of money was spent as follows: On the first day 10 percent of the amount in the 2nd rest day and 30 percent of the remaining 40 lei. Learn initial amount. [Trouble cent]
</span>The Initial Amount is 0.00075.

<span>Suma inițială este de 0,00075.</span>

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The square root of 9/16

saw5 [17]

3/4 or 0.75 hope this helps :)

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3 years ago

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Tiny's Tattoo Parlor sold 389 tattoos this month. 43 of those tattoos were arm tattoos. Based on this data, what is a reasonable

antiseptic1488 [7]

Answer
(389-43)/389=346/389

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3 years ago

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A plot of land has an area of 1,089,000 square feet.The conversion factors between different area measures are shown below.27,87

IgorC [24]

Part A) 24.79 acres

1) Since that plot has an area of

$1,089,000ft^2=1.08\times10^6ft^2$

And the number of units must be between 10 and 10² units.

Part A)

$\begin{gathered} 27,878,400ft^2=2.78784\times10^7ft^2=1m^2 \\ 43560ft^2\text{ =4.356 }\times10^4ft^2\text{ = 1 acre} \end{gathered}$

2) Let's convert them to the apparently plausible units, see if it fits within the given interval.

$\begin{gathered} \frac{1.08\times10^6}{4.356\times10^4}=24.79\text{ acres} \\ \frac{1.08\times10^6}{2.78784\times10^7}=0.03m^{2} \end{gathered}$

We can see that 0.03 m² does not belong to the given interval.

3) Hence, the answer is 24.79 acres.

7 0

1 year ago

Suppose a production line operates with a mean filling weight of 16 ounces per container. Since over- or under-filling can be da

miss Akunina [59]

Answer:

From the question we are told that

The population mean is $\mu = 16$

The sample size is n = 30

The sample mean is $\= x = 16.32$

The population standard deviation is $\sigma = 0.8$

The level of significance is $\alpha = 0.10$

Step 1: State hypotheses:

The null hypothesis is $H_o : \mu = 16$

The alternative hypothesis is $H_a : \mu \ne 16$

Step 2: State the test statistic. Since we know the population standard deviation and the sample is large our test statistics is

$t = \frac{ \= x -\mu }{ \frac{\sigma}{ \sqrt{n} } }$

=> $t = \frac{ 16.32 -16 }{ \frac{0.8 }{ \sqrt{30} } }$

=> $t =2.191$

Generally the degree of freedom is mathematically represented as

$df = n - 1$

=> $df = 30 - 1$

=> $df =29$

Step 3: State the critical region(s):

From the student t-distribution table the critical value corresponding to $\alpha = 0.10$ is

$t = 1.311$

Generally the critical regions is mathematically represented as

$- 1.311 < T < 1.311$

Step 4: Conduct the experiment/study:

Generally the from the value obtained we see that the t value is outside the critical region so the decision is [Reject the null hypothesis ]

Step 5: Reach conclusions and state in English:

There is sufficient evidence to show that the filling weight has to be adjusted

Step 6: Calculate the p-value associated with this test. How does this the p-value support your conclusions in Step 5?

From the student t-distribution table the probability value to the right corresponding to $t =2.191$ at a degree of freedom of $df =29$ is

$P( t > 2.191) = 0.0183$

Generally the p-value is mathematically represented as

$p-value = 2 * P( t > 2.191 )$

=> $p-value = 2 * 0.0183$

=> $p-value = 0.0366$

Generally looking at the value obtained we see that $p- value < \alpha$ hence

The decision rule is

Reject the null hypothesis

Step-by-step explanation:

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3 years ago

Keesha has 24 beads to add equally to each bag . Can she still make 6 bags and have no supplies left over.

svetoff [14.1K]

Answer:

Yes, she would put 4 beads in each bag

Step-by-step explanation:

24 ÷ 6 = 4

6 0

3 years ago