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Svetllana [295]
3 years ago
13

The amount of money, in dollars, Sarah has in her savings account is modeled as a function of time in months. This function is r

epresented by the graph below. What is the average rate of change for the amount of money, in dollars per month, from month 0 to month 12? A $25 per month B $50 per month C $300 per month D $500 per month

Mathematics
2 answers:
hjlf3 years ago
6 0

Answer:

330.60.330.60.330.60.

Step-by-step explanation:

Illusion [34]3 years ago
3 0

Answer:

The average rate of change for the amount of money is A) $25 per month

Step-by-step explanation:

From the graph we can see Sarah earn $50 every two months, 50/2 = 25/1 so we can determine Sarah's average rate of change from month 0 to month 12 is $25 dollars per month. Hope this helped, let me know if you have any questions! :)

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AABC is isosceles.<br> AB = 3x - 4 and BC = 5x - 10.<br> AB = [?]
Schach [20]

If AB = BC then set up the equation 3x - 4 = 5x - 10

Subtract 3x.

-4 = 2x - 10

Add 10.

6 = 2x

Divide by 2.

3 = x

AB is 3x - 4 so

3(3) - 4

9 - 4

5.

AB = 5

If AB is not equal to BC then this is not solvable.

But if they are I am sure AB = 5.

Hope this helps

4 0
3 years ago
The table gives the boiling point of water at different altitudes.
stich3 [128]
Slope = raise / run

(211.1 - 212.0) / (0.5-0) = - 1.8

(210.2 - 211.1) / (1.0-0.5) = - 1.8

(208.4 - 210.2) / (2.0 - 1.0) = - 1.8

You can check, the other points. The slope is constant because the function is a linear equation,

Answer: - 1.8
4 0
3 years ago
Liam says - (5/12) is equivalent to 5/-12. Explain if Liam is correct by completing the statements below.
makkiz [27]

A positive number divided by a positive number results in a negative quotient, and it's opposite is always positive. The fraction 5/-12 can be described as a positive number divided by a negative number, which always results in a negative quotient. The fractions have different value, so Liam is not correct.

6 0
3 years ago
Read 2 more answers
Find an equation of the line(-2,-9) and(-7,-3)
andriy [413]

Answer:

The required equation is 6x+5y+57=0.

3 0
3 years ago
A train traveled from Station A to Station B at an average speed of 80 kilometers per hour and then from Station B to Station C
earnstyle [38]

Answer:

(i). Average speed = 75 km per hour

(ii). Average speed = 75 km per hour

Step-by-step explanation:

This question is incomplete; here is the complete question.

A train traveled from station A to station B at an average speed of 80 kilometers per hour and then from station B to station C at an average of 60 kilometers per hour. If the train did not stop at station b, what was the average speed at which the train traveled from station A to C?

(i). The distance that the train traveled from station A to station B was 4 times the distance that train traveled from station B to station C.

(ii). The amount of time it took to the train to travel from station A to station B is 3 times the amount of time that it took the train to travel from station B to station C.

(i) Let the distance between station B and station C = x km

So the distance between Station A and station B = 4x km

Therefore, time to travel the distance x km with 80 km per hour = \frac{\text{Distance traveled}}{\text{Speed}}

= \frac{4x}{80}

Similarly time taken to travel between station B and station C with speed 60 km per hour = \frac{x}{60} km per hour

Now average speed between station A and station C = \frac{\text{Total distance between station A and station C}}{\text{time taken to travel}}

= \frac{4x+x}{\frac{4x}{80}+\frac{x}{60}}

= \frac{5x}{\frac{4x}{60} }

= \frac{5\times 60}{4}

= 75 km per hour

(ii). Let the train took the time to cover the distance between station B and station C = t hours

Therefore, time taken by the train between station A and B = 3t

Distance between Station A and station B = Speed × time

= 80 × 3t

= 240t km

Similarly distance between station B and station C = 60 × t

= 60t

Now average speed between station A and station C = \frac{240t+60t}{(3t+t)}

= \frac{300t}{4t}

= 75 km per hour

4 0
3 years ago
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