Answer:
It'll take 7 hours for the car B to cath up to A
Step-by-step explanation:
In order to solve this problem we can write the equation from the distance of each car. Assuming that t = 0 happens when the second car leaves Toronto. When the second car leaves Toronto, the first one is on the road for two hours already, thefeore it travelled a total of:
distance = speed*time = 70*2 = 140
We have:
Car A:
x(t) = 70*t + 140
Car B:
x(t) = 90*t
We now need to find the value of "t" that makes x(t) the same for both cars:
90*t = 70*t + 140
20*t = 140
t = 140 / 20 = 7 h
17.5 i think I’m not sure though.
Answer:
10000 x (1.001438)^4t
Step-by-step explanation:
Using the compound interest formula Accrued Amount = P (1 + r/n)^n t
where Accrued amount is to be determined
P = principal; $10000
r = 5.75% = 0.0575
n = number of times interest is applied annually = 4 for quarterly
t = number of years
Therefore
Accrued Amount (A) = 10000 x (1 + (0.0575/4))^(4t)
= 10000 x (1 + (0.001438))^(4t)
= 10000 x (1.001438)^4t
which can then be solved by varying t, the number of years
A=3.14(pi)r(r+h2+r2) Hope this helps!
