1. Part A: We know parts of our triangle since the cosine of X is given. XY = 2.5 and XZ = 5.59 and since it is a scale factor of 2, ABC is most likely similar to XYZ by angle measures and the special relationship is, that they are all equal, because with a scale factor of two, all the ratios in triangle ABC will simplify to the ratios of triangle XYZ.

Part B: Because triangle XYZ was dilated with a scale factor of 2 to create triangle ABC, just multiply the sides by 2 to get the sides AC and CB, which is AB = 2 times XY and CB = 2 times XZ.

2. We can first find the hypothenuse by adding squaring 8 and 6 to have 100. Then square root it to have 10 as our hypothenuse

Now we can use sin x = 6/10 and cos y = 6/10

3. Since this is using the angle of elevation, we can say that the length of side AB is perpendicular from the perspective of angle of elevation, and the hypotenuse's length is known, so in this case, we can use a sine or cosecant ratio.

Sin(40 Degrees) = AB/100

AB = 100 x sin(40 Degrees) ft

AB ~ 64.28 ft which can be rounded to 64 ft

The triangle I drew was a right triangle with points A, B, and C. 40 is on point C while 100 ft was on the hypotenuse. The kite was near A and the ground was between segment B and C.

4. Since the angle and Adjacent line is given and it is asking us to find H which is the opposite, we well try and be using Tangent = opposite/adjacent

500 ft Multiply by tan39 = 405 (Estimated after rounding to nearest hundreth 404.892).

To be honest, I didn't know so much about these questions but this might give a better understanding and if I'm wrong then I apologize.

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2 years ago