Answer:
Part 1) 
Part 2) 
Part 3) 
The answer is the option A
Step-by-step explanation:
Part 1) Find the measure of side HI
Applying the Pythagoras Theorem
substitute the values and solve for HI
Part 2) Find the measure of angle G
In the right triangle GHI
substitute the values
Part 3) Find the measure of angle I
Remember that
The sum of the interior angles of a triangle must be equal to 180 degrees
so
substitute the values
Jamal and Steve finished the same amount of homework because 5/6 is the same as 10/12
In order to find which <u>expression</u> is <u>equivalent</u> to ![\sqrt[4]{x^{10}},](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E%7B10%7D%7D%2C)
<u>simplify</u> all given expressions:
0.
![\sqrt[4]{x^{10}}=x^{\frac{10}{4}}=x^{\frac{5}{2}}=x^{2.5}.](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7Bx%5E%7B10%7D%7D%3Dx%5E%7B%5Cfrac%7B10%7D%7B4%7D%7D%3Dx%5E%7B%5Cfrac%7B5%7D%7B2%7D%7D%3Dx%5E%7B2.5%7D.)
1.
![x^2(\sqrt[4]{x^2})=x^2\cdot x^{\frac{2}{4}}=x^2\cdot x^{\frac{1}{2}}=x^2\cdot x^{0.5}=x^{2.5}.](https://tex.z-dn.net/?f=x%5E2%28%5Csqrt%5B4%5D%7Bx%5E2%7D%29%3Dx%5E2%5Ccdot%20x%5E%7B%5Cfrac%7B2%7D%7B4%7D%7D%3Dx%5E2%5Ccdot%20x%5E%7B%5Cfrac%7B1%7D%7B2%7D%7D%3Dx%5E2%5Ccdot%20x%5E%7B0.5%7D%3Dx%5E%7B2.5%7D.)
2.
3.
![x^3(\sqrt[4]{x} )=x^3\cdot x^{\frac{1}{4}}=x^3\cdot x^{0.25}=x^{3.25}.](https://tex.z-dn.net/?f=x%5E3%28%5Csqrt%5B4%5D%7Bx%7D%20%29%3Dx%5E3%5Ccdot%20x%5E%7B%5Cfrac%7B1%7D%7B4%7D%7D%3Dx%5E3%5Ccdot%20x%5E%7B0.25%7D%3Dx%5E%7B3.25%7D.)
4.
Therefore,
Answer: correct choice is A
Answer:
(This is for the pizza question)The area of the box is 900 cm, so subtract 900 cm from the area of the circle which is (3.14)[times radius which is 12(half of 24) squared] [144*3.14] So the area of the circle is 452.16 which you get from the area formula of pi times radius squared.
Step-by-step explanation:
Find the area of the box first, then subtract it by the area of the circle. (please thank me for it)
I can't answer this question if we don't know by what scale the cylinder's radius was reduced. Luckily, I found the same problem that says the radius was reduced to 2/5. So, we find the ratio of both volumes.
V₁ = πr₁²h₁
V₂ = πr₂²h₂
where r₂ = 2/5*r₁ and h₂ = 4h₁
V₂/V₁ = π(2/5*r₁ )²(4h₁)/πr₁²h₁= 8/5 or 1.6
<em>Thus, the volume has increased more by 60%.</em>
