(72÷2)³ - 7 · 9 ÷ 9
First, parenthesis
72÷2 is 36
Next, exponents.
36³ is 46656.
Then, multiplication.
7 · 9= 63
After that, division.
63 ÷ 9 is 7
Finally, subtraction.
46656 - 7 is 46649
If A=38x-x^2 then
dA/dx=38-2x
d2A/dx2=-2
Since the acceleration, d2A/dx2 is a constant negative, when velocity, dA/dx=0, it will be an absolute maximum for A(x)
dA/dx=0 only when 38=2x, x=19
A(19)=38(19)-19^2
A(19)=722-361
A(19)=361 ft^2
So the maximum possible area is 361 ft^2
(This will always be true as the maximum possible area enclosed by a given amount of material will always be a perfect square...)
Answer: k = -8/9j + -1/9m + 1
Step 1: Flip the equation.<span><span><span><span>−8j </span>− 9k </span>+ 9 </span>= m
</span>Step 2: Add -9 to both sides.<span><span><span><span><span>−8j </span>− 9k </span>+ 9 </span>+ −9 </span>= <span>m + −9</span></span><span><span><span>−8j </span>− 9k </span>= <span>m − 9
</span></span>Step 3: Add 8j to both sides.<span><span><span><span>−8j </span>−9k </span>+ 8j </span>= <span>m −9 + 8j</span></span><span><span>−9k </span>= <span><span>8j + m </span>−9
</span></span><span>Step 4: Divide both sides by -9.
-9k/-9 = 8j + m - 9/-9
</span><span>k = -8/9j + -1/9m + 1</span>
Answer:
We could see the graph of all of the three questions of the quadrilaterals as is attached with the answer.
Ques 14)
The vertices of quadrilateral is given as:
W(-1,1),X(0,2),Y(1,2),Z(0,-2)
Ques 15)
The vertices of the quadrilateral is given as:
R(-2,-3) , S(4,0), T(3,2) and V(-3,-1)
Ques 18)
The vertices of the quadrilateral are given as:
E(-3,1), F(-7,-3) ,G(6,-3) and H(2,1)
Answer:
A = 1, B = 1
Step-by-step explanation:
From the question
(2x+1)/(x²+x) = A/x + B/(x+1)
(2x+1)/(x²+x) = [A(x+1)+(Bx)]/(x²+x)
Equation the numerator
2x+1 ≡ A(x+1) +Bx
2x+1 ≡ Ax+A+Bx
From the above,
A = 1.
And,
2x = Ax+Bx................ Equation 1
A+B = 2
Substitute the value of A into Equation 1
1+B = 2
B = 2-1
B = 1
