1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Bezzdna [24]
3 years ago
9

How do you solve linear equations by subsitutions

Mathematics
1 answer:
TiliK225 [7]3 years ago
5 0
1) First, solve one linear equation for y in terms of x .

2) Then substitute that expression for y in the other linear equation.

3)Solve this, and you have the x -coordinate of the intersection.

4)Then plug in x to either equation to find the corresponding y -coordinate.


You might be interested in
7g + 4g + 3g − 13g + g = 10 please help!!
Leona [35]
Combine like terms.


7g + 4g + 3g + g = 15g

15g - 13g = 2g


2g = 10


Divide by 2 on both sides.


g = 5
5 0
3 years ago
Read 2 more answers
Can someone PLEASE tell me the answer to this
Serjik [45]

Answer:

third option is the correct answer

go with the names of the triangle

the triangles are HIJ and LMN

so the ratios will be accordingly

5 0
2 years ago
Read 2 more answers
PLEASE SOMEONE BLESS UP AND HELPPP MEEEE AND ILL MARK YOU BRAINLIEST THANKSSSS
Assoli18 [71]
It’s t20=20

I am doing the same thing in math
8 0
2 years ago
Use the principle of inclusion and exclusion to find the number of positive integers less than 1,000,000 that are not divisable
wel
This is a simple problem based on combinatorics which can be easily tackled by using inclusion-exclusion principle.
We are asked to find number of positive integers less than 1,000,000 that are not divisible by 6 or 4.
let n be the number of positive integers.
∴ 1≤n≤999,999
Let c₁ be the set of numbers divisible by 6 and c₂ be the set of numbers divisible by 4.
Let N(c₁) be the number of elements in set c₁ and N(c₂) be the number of elements in set c₂.

∴N(c₁) = \frac{999,999}{6} = 166666
N(c₂) = \frac{999,999}{4} = 250000
∴N(c₁c₂) = \frac{999,999}{24} = 41667
∴ Number of positive integers that are not divisible by 4 or 6,

N(c₁`c₂`) = 999,999 - (166666+250000) + 41667 = 625000
Therefore, 625000 integers are not divisible by 6 or 4
8 0
3 years ago
Of a group of students 5/8 of them are boys. The girls are put into groups so that each group has 1/6 of the total number of stu
Marina86 [1]
I believe the answer is 9.
3 0
2 years ago
Other questions:
  • Share 72 sweets in the ratio 8:1
    14·2 answers
  • Explain how to use the combine place value strategy to find 223 -119.
    6·1 answer
  • If one container holds 55 balls, how many balls will nine containers hold?
    10·2 answers
  • What is the circumference of a circle with radius 3 cm to the nearest hundredth
    10·2 answers
  • Convert the decimal 0.92 to a fraction.<br>83/9<br>83/90<br>83/100<br>92/99​
    13·1 answer
  • These box plots show daily low temperatures for a sample of days In two different towns
    13·2 answers
  • Which problem can be solved using the equation 9x + 14 = 100
    6·1 answer
  • Please help me with this problem!!
    12·1 answer
  • Whats type of account has a fixed interest rate, a term and a fixed date of<br> withdrawal? *
    6·1 answer
  • Simplify the expression:<br> 2x+1bx8
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!