The speed of slower bus is 118 km/hr and speed of faster bus is 133 km/hr
<h3>What is speed?</h3>
Speed is a scalar quantity that refers to "how fast an object is moving".
Given that, two buses leave a station at the same time and travel in opposite directions, one bus travels 15 km/h faster than the other, the two buses are 1004 kilometres apart after 4 hours,
Speed = distance/ time
Let the speed of the slower bus be v and the faster bus be (v+15)
According to the question,
vt + (v+15)t = 1004
vt + vt + 15t = 1004
t = 4
4v + 4v + 60 = 1004
8v = 944
v = 118
Hence, The speed of slower bus is 118 km/hr and speed of faster bus is 133 km/hr
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Answer:
Step-by-step explanation:
Use math-way go quick and easy answers without step by step explanations, and use math-soup-calculator for step by step explanation
you just need to multiply the length times width
Given multiplication:
(3√6 - √2)(4√2 - √6)
= 3√6(4√2-√6)-√2(4√2-√6)
= 3√6*4√2 - 3√6*√6 - √2*4√2 + √2*√6
= 12√12 -3√(6*6) -4√(2*2) + √(2*6)
= 12√(4*3) - 3√(36) - 4√(4) + √(12)
= 12*2√3 - 3*6 - 4*2 + 2√3
= 24√3 - 18-8 +2√3
= 24√3 + 2√3 - 18-8
= 26√3 - 18-8
= 26√3 - 26
= 26(√3-1).
<u>Answer</u><u>:</u><u>-</u> (3√6 - √2)(4√2 - √6) = 26(√3-1)
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