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4 years ago

Which of the following coordinates is a solution to the linear equation?

1 answer:

7 0

Right this is pretty simple all you do is sub the points to the equation given.
So first try the first point (2,-1) in y=-3x+7
==> -1=-3(2)+7
==>-1=1 this is not equal therefore not the right points

Then try (1,10)
==>10=-3(1)+7
==>10=4 this is incorrect therefore not the right points

Next try (3,-2)
==>-2=-3(3)+7
==>-2=-2 this is equal therefore this is the coordinates to the linear equation.

Finally try the last points to make sure you are correct.
==> -8=-3(-5)+7
==>-8=22 this is incorrect also.

Therefore the only coordinates that satisfies the equation is (3,-2)

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3 years ago

Convert 240 pounds per square inch into a unit rate of tons per square foot

tester [92]

Answer:

240 x 144 inches= 34,560 pounds per square foot

34560/2000= 17.28 tons per square foit

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3 years ago

Quadrilateral ABCD with vertices A(0, 6), B(-3, -6), C(-9, -6), and D(-12, -3): a) dilation with scale factor of 1/3 centered at

Oksanka [162]

a) The points of the new quadrillateral are $A'(x,y) = (0, 2)$ , $B'(x,y) = (-1, -2)$ , $C'(x,y) = \left(-3,-2\right)$ and $D'(x,y) = (-4, -1)$ , respectively.

b) The points of the new quadrillateral are $A'(x,y) = (-5, 5)$ , $B'(x,y) = (-8,-7)$ , $C'(x,y) = (-13, -7)$ and $D'(x,y) = (-17, -4)$ , respectively.

<h3>How to perform transformations with points</h3>

a) A dillation centered at the origin is defined by following operation:

$P'(x,y) = k\cdot P(x,y)$ (1)

Where:

$P(x,y)$ - Original point
$P'(x,y)$ - Dilated point.

If we know that $k = \frac{1}{3}$ , $A(x,y) = (0,6)$ , $B(x,y) = (-3,-6)$ , $C(x,y) = (-9, -6)$ and $D(x,y) = (-12, -3)$ , then the new points of the quadrilateral are:

$A'(x,y) = \frac{1}{3}\cdot (0,6)$

$A'(x,y) = (0, 2)$

$B'(x,y) = \frac{1}{3} \cdot (-3,-6)$

$B'(x,y) = (-1, -2)$

$C'(x,y) = \frac{1}{3}\cdot (-9,-6)$

$C'(x,y) = \left(-3,-2\right)$

$D'(x,y) = \frac{1}{3}\cdot (-12,-3)$

$D'(x,y) = (-4, -1)$

The points of the new quadrillateral are $A'(x,y) = (0, 2)$ , $B'(x,y) = (-1, -2)$ , $C'(x,y) = \left(-3,-2\right)$ and $D'(x,y) = (-4, -1)$ , respectively. $\blacksquare$

b) A translation along a vector is defined by following operation:

$P'(x,y) = P(x,y) +T(x,y)$ (2)

Where $T(x,y)$ is the transformation vector.

If we know that $T(x,y) = (-5,-1)$ , $A(x,y) = (0,6)$ , $B(x,y) = (-3,-6)$ , $C(x,y) = (-9, -6)$ and $D(x,y) = (-12, -3)$ ,

$A'(x,y) = (0,6) + (-5, -1)$

$A'(x,y) = (-5, 5)$

$B'(x,y) = (-3, -6) + (-5, -1)$

$B'(x,y) = (-8,-7)$

$C'(x,y) = (-9, -6) + (-5, -1)$

$C'(x,y) = (-13, -7)$

$D'(x,y) = (-12,-3)+(-5,-1)$

$D'(x,y) = (-17, -4)$

The points of the new quadrillateral are $A'(x,y) = (-5, 5)$ , $B'(x,y) = (-8,-7)$ , $C'(x,y) = (-13, -7)$ and $D'(x,y) = (-17, -4)$ , respectively. $\blacksquare$

To learn more on transformation rules, we kindly invite to check this verified question: brainly.com/question/4801277

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3 years ago

3/5x + 35°<br>Find the value of x.<br>135<br>145<br>quizzes

lapo4ka [179]

Answer:

⅕x (3x + 175)

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3 years ago

Target sells a pack of iTunes gift cards for $40. Sam's Club sells them for $38.88. What is the percent decrease from Target's p

patriot [66]

We have been given that target sells a pack of iTunes gift cards for $40. Sam's Club sells them for $38.88. We are asked to find the percent decrease from Target's price to Sam's Club's price.

We will use percent decrease formula to solve our given problem.

$\text{Decrease percent}=\frac{|\text{Final}-\text{Initial}|}{\text{Initial}}\times 100\%$