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olga_2 [115]
3 years ago
13

im looking for a number that is greater than 0.8 but less than 0.9. The greatest digit is in the hundredths place. What could th

e number be?
Mathematics
1 answer:
DaniilM [7]3 years ago
5 0
I hope this helps 0.7
You might be interested in
According to the Complex Conjugate Root Theorem, if a+bi is a root of a quadratic equation, then __blank__ is also a root of the
Trava [24]

Answer:

a-bi


Step-by-step explanation:

If a quadratic equation lx^2+mx+n=0 has one imaginary root as a+bi then the other root is the conjugate of a+bi = a-bi

Because we have l, m and n are real numbers and they are the coefficients.

Sum of roots = a+bi + second root = -m/l

When -m/l is real because the ratio of two real numbers, left side also has to be real.

Since bi is one imaginary term already there other root should have -bi in it so that the sum becomes real.

i.e. other root will be of the form c-bi for some real c.

Now product of roots = (a+bi)(c-bi) = n/l

Since right side is real, left side also must be real.

i.e.imaginary part =0

bi(a-c) =0

Or a =c

i.e. other root c-bi = a-bi

Hence proved.


3 0
3 years ago
Select the equation of the line parallel to the equation y = -2x - 7 that passes through the point (3, 1).
sasho [114]
Y = -2x - 7 
slope = -2 (parallel shares the same slope, -2)

Option A:
y = -2x + 7
slope = -2

At (3, 1)
y = -2(3) + 7 = 1

Answer: Option A
7 0
3 years ago
(10-3)*2+(5-14/2 help
Dafna11 [192]
2(10-3) distribute = 2*10 is 20 and 2*3 is 6
20-6+(5-14/2)
now 20-6 is 14
14+(5-14/2)
now 14/2 is 7
14+(5-7)
now 5-7 is -2
14+-2
is 12 
the answer is 12
but if you want to you can do 12/3 to get the greatest common factor 
which is 4
hope i help you :P 
6 0
3 years ago
Read 2 more answers
I have a stamp collection. 70% of my stamps are Canadian and 30% are international. I have 500 more Canadian stamps than interna
shutvik [7]

Answer: N= 375, C= 875

Step-by-step explanation:  Let Canadian stamps=C

Let International stamps=N

C=875     and        N=375

 

C - 500=N,  .70(N + C) =C

Solve the following system:

{C-500 = N |     (equation 1)

0.7 (C+N) = C |     (equation 2)

Express the system in standard form:

{-N+C = 500 |     (equation 1)

0.7 N-0.3 C = 0 |     (equation 2)

Add 0.7 × (equation 1) to equation 2:

{-N+C = 500 |     (equation 1)

0 N+0.4 C = 350 |     (equation 2)

Divide equation 2 by 0.4:

{-N+C = 500 |     (equation 1)

0. N+C = 875. |     (equation 2)

Subtract equation 2 from equation 1:

{-N+0 C = -375. |     (equation 1)

0 N+C = 875. |     (equation 2)

Multiply equation 1 by -1:

{N+0 C = 375. |     (equation 1)

0 N+C = 875. |     (equation 2)

Collect results:

Answer: |  N = 375        and             C=875

3 0
2 years ago
Alfonso and Lucas are 238 miles apart, traveling towards each other. If Lucas travels 21 mph and Alfonso travels 13 mph how long
Alex

Lucas equation for his location is x(t) = 13t.

Alfonso's equation is x(t) = 238 - 21t

If you equate these, you get:


13t = 238 - 21t =>

34t = 238

t = 7


So after seven hours they meet.

7 0
3 years ago
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