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Zarrin [17]
3 years ago
7

A box of colored crayons contains 16 distinct colors. In how many ways can 14 colors be chosen, assuming that the order of the c

olors chosen doesn't matter?
Mathematics
2 answers:
Harrizon [31]3 years ago
6 0
Could you rephrase that? Is it just 14 multiplied by 14?
hram777 [196]3 years ago
5 0

Answer:

16 choose 14

Step-by-step explanation:

16 choose 14, If you do the math it will be correct.

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3 years ago
Complete the square to the problem X^2+6x-16=0
marishachu [46]

Answer:

<h2>x = -8 or x = 2</h2>

Step-by-step explanation:

(a+b)^2=a^2+2ab+b^2\qquad(*)\\\\-------------------------------\\\\x^2+6x-16=0\qquad\text{add 16 to both sides}\\\\x^2+6x=16\\\\x^2+2(x)(3)=16\qquad\text{add}\ 3^2\ \text{to both sides}\\\\\underbrace{x^2+2(x)(3)+3^2}_{(*)}=16+3^2\\\\(x+3)^2=16+9\\\\(x+3)^2=25\Rightarrow x+3=\pm\sqrt{25}\\\\x+3=-5\ \vee\ x+3=5\qquad\text{subtract 3 from both sides}\\\\\boxed{x=-8\ \vee\ x=2}

3 0
4 years ago
What is<br> 5 1/6 - 5 1/2
Ymorist [56]

Answer:

1/3

Step-by-step explanation:

51/6 = 51/6

51/2= 5 3/6

= 2/6

6 0
3 years ago
Read 2 more answers
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