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jolli1 [7]
3 years ago
14

I WILL AWARD BRAINLIEST IF CORRECT!!

Mathematics
1 answer:
solmaris [256]3 years ago
3 0
1kg=1000g so if it would be 80% it would be 20% left since 1000 is a proper percent we could determine that 800g
Is lost and we have 200g left or 2/10KG
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that would be correct

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The dingram shows a spinner innde up of a picce of card in the shape of a regular pentagon, with a toothpick pushed through its
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Answer:

a) P(X \leq 3) = 0.99328

b) 0.6957

Step-by-step explanation:

Let X represent the number of 4's when  n = 5 independent spins

each has a probability of 0.2 (i.e p = 0.2)

This notation is represented as:

X \approx Binomial (n = 5, p = 0.2)

Probability of  x  number of 4's is:

P(X=x)= (\left \ n \atop x \right) p^x (1-p)^{(n-x)}

here; (\left \ n \atop x \right) is the combinatorial expression

(\left \ n \atop x \right) = \frac{n!}{x!(n-x)!}

P(X \leq3), n =5 , p = 0.2

P(X \leq3) = 1-P(X > 3)

So; let's first find:

P(X > 3)

= P(3

P(X = 4) =( \left \ {{5} \atop {4}} \right. ) (0.2)^4 (1-0.2)^1  \\ \\ P(X = 4) = 5(0.2)^4(0.8)^1 \\ \\ P(X = 4) = 0.0064

P(X = 5) =( \left \ {{5} \atop {5}} \right. ) (0.2)^5 (1-0.2)^0  \\ \\ P(X = 5) = 5(0.2)^5(0.8)^0 \\ \\ P(X = 5) = 0.00032

P (X=4)+P(X  = 5 ) \\ \\  = 0.0064 + 0.00032 = 0.006720  \\ \\ \approx 0.007

P(X > 3 ) = 0.00672 \\ \\ P(X \leq 3) = 1- P(X > = 3 ) \\ \\ =1 - 0.00672  \\ \\ = 0.99328

P(X \leq 3) = 0.99328

b)

Given that:

The ratio of boys to girls at birth in  Singapore is quite high at 1.09:1

What proportion of Singapore families with exactly 6 children will have at least 3 boys?

Probability of having a boy = \frac{1.09}{1+1.09} = 0.5215

Binomial Problem with n = 6

P(3<= x <=6) = 1 - P(0<= x <=2)

= 1 - binomial (6,0.5215,2)

= 0.6957

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