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shepuryov [24]
3 years ago
13

65pts! plot the vertex and the axis of symmetry of this function:

Mathematics
2 answers:
Mashcka [7]3 years ago
4 0

Answer:

f(x)=(x−3)2−5

Find the properties of the given parabola.

Direction:

Vertex: (3,−5)

Focus: (3,−194)

Axis of Symmetry: x=3

Directrix: y=−214

Select a few x

values, and plug them into the equation to find the corresponding y values. The x

values should be selected around the vertex.

x  y

1   -1

2  -4

3   -5

4   -4

5    -1

Graph the parabola using its properties and the selected points.

Direction:

Vertex: (3,−5)

Focus: (3,−194)

Axis of Symmetry: x=3

Directrix: y=−214

x  y

1   -1

2  -4

3   -5

4   -4

5    -1

nadezda [96]3 years ago
4 0

Answer:

I can do it but not at now

So.. I will solve this later

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<h2><u>Given:</u><u>-</u></h2>

  • Points C = (-7,2) → \sf{(X_1,Y_1)}
  • D = (3,12) → \sf{(X_2,Y_2)}

<h2><u>To </u><u>Find</u><u>:</u><u>-</u></h2>

  • The Midpoint of CD.

<h2><u>Required</u><u> </u><u>Response</u><u>:</u><u>-</u></h2>

Let,

Midpoint of CD be (x,y).

WKT,

\boxed{\sf{(x,y) = \frac{X_1+X_2}{2},\frac{Y_1+Y_2}{2}}}

→\;{\sf{\frac{-7+3}{2},\frac{2+12}{2}}}

→\;{\sf{\frac{-4}{2},\frac{14}{2}}}

→\;{\sf{-2,7}}

The Midpoint of CD ◕➜ \Large{\red{\mathfrak{(-2,7)}}}

Let,

The centre be O

Radius = CO & OD

Here, C = (-7,2) → \sf{(X_1,Y_1)}

O = (-2,7) → \sf{(X_2,Y_2)}

\boxed{\sf{Distance = \sqrt{(X_2-X_1)²+(Y_2-Y_1)²}}}

→\;{\sf{\sqrt{(-2+7)²+(7-2)²}}}

→\;{\sf{\sqrt{5²+5²}}}

→\;{\sf{\sqrt{25+25}}}

→\;{\sf{\sqrt{50}}}

→\;{\sf{5√2 (or) 7.07}}

Radius of Circle ◕➜ \Large{\red{\mathfrak{7.07}}}

<h2>Option D.</h2>

Hope It Helps You ✌️

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