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Artist 52 [7]
3 years ago
5

A typist is entering text on keyboard at the rate of 30 words per minute. if each word is 6 characters long on average, what ban

dwidth in bits per second between the keyboard and main memory is required to transmit the information? a space is also a character. assume that each word is followed by a space?
Computers and Technology
2 answers:
IrinaVladis [17]3 years ago
6 0

In 1 minute --------30 words

means  (30 x 6) + 29 characters   [29 for spaces]

means  { (30 x 6) +29 } x 8 bits = 1672 bits

in 1 minute or 60 second it is 1672 bits

in 1 sec it is 27.867 bits

number of bits being sent per second is 27.867 bits

Makovka662 [10]3 years ago
3 0

Answer:

27.827 bits per second

Explanation:

In the field of computers, bandwidth refers to the maximum rate of data transfer; in this particular case, we are talking about data bandwidth in bits/seg, to calculate it we follow these steps:

  1. Find the number of letters per minute: We have 30 words per minute and each word is made of 6 letters, therefore, the amount of letters without spaces is -> 30 * 6 = 180 letters/min
  2. Find the number of characters per minute: If each word is separated by space we will have 29 spaces because the last word doesn't need space. To find the total amount of characters we add letters and spaces -> 180 + 29 = 209 characters per minute
  3. Find the number of bits: In a standard computer each character in the ASCII format is made out of 8 bits, therefore, the total number of bits is equal to the total number of characters multiply by the bits per character -> 209 * 8 = 1672 bits/min
  4. Find the bandwidth in bits/seg: To complete the process we convert our previous result of bits/min to bits/seg -> 1672/60 = 27.867 bits/seg

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Answer:

\textsf{\large{\underline{Solution}:}}

The given problem is solved using language - Python.

def f(x):

   new_list=[]

   for i in x:

       if i%2==0:

           new_list.append(i//2)

       else:

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   return new_list

   

my_list=list(range(1,6))

print('Original List:',my_list)

my_list=f(my_list)

print('Modified List:',my_list)

\textsf{\large{\underline{Logic}:}}

  1. Create a new list.
  2. Iterate over the list passed into the function.
  3. Check if the element is even or not. If true, append half the value of element in the list.
  4. If false, append twice the value of the element in the list.
  5. At last, return the new list.

There is another way of doing this - By using map() function.

—————————————————————————————

def f(x):

   return list(map(lambda x:x//2 if x%2==0 else 2*x,x))

   

my_list=list(range(1,6))

print('Original List:',my_list)

my_list=f(2my_list)

print('Modified List:',my_list)

—————————————————————————————

\textsf{\large{\underline{O{u}tput}:}}

Original List: [1, 2, 3, 4, 5]

Modified List: [2, 1, 6, 2, 10]

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