Your answer would be 5.10... Hope this helps :)
Answer:
70
Step-by-step explanation:
First, to find the constant rate divided 20 miles by 8 days.
20 ÷ 8 = 2.5
Then, we know that in one week there are seven days so we multiply 2.5 x 7
2.5 x 7 = 17.5
Lastly, multiply 17.5 times 4
17.5 x 4 = 70
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3940 centimeters
Each 100 centimeters is 1 meter
Answer:
P = 0.0438 ; We reject the Null and conclude that there is significant evidence that the discharge limit per gallon of waste has been exceeded.
Due to the small sample size.
Step-by-step explanation:
H0: μ = 500
H1 : μ > 500
Test statistic :
(xbar - μ) / S.E
Tstatistic = (1000 - 500) / 200
= 500 / 200
= 2.5
Pvalue from Test score ; df = 4 - 1 = 3 ; using calculator :
Pvalue = 0.0438
At α = 0.05
Pvalue < α ; We reject the Null and conclude that there is significant evidence that the discharge limit per gallon of waste has been exceeded.
The test above has a very small sample size, and for a distribution to be approximately Normal, the sample size must be sufficiently large enough according to the Central limit theorem.
For a two sided analysis ; the Pvalue is twice that for the one sided, hence, Pvalue = (0.0438 * 2) = 0.0876 yielding a less strong evidence against the Null.
Answer:
-(2x+1) ,6x-8x=-2x,+1-2=1