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Anettt [7]
3 years ago
10

PLZ HELP Due in an hour!

Mathematics
1 answer:
Dafna11 [192]3 years ago
6 0

Answer:

77/200

Step-by-step explanation:

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Given the lengths of two sides of a triangle, find the range for the length of the third side (between what two numbers should t
Paraphin [41]
The triangle inequality tells you the third side will be between the difference and sum of the other two sides.

5 < third side < 21
6 0
3 years ago
The 17th term of an Arithmetic sequence is 51. If the commons difference is 7, what is the first term ?
vovikov84 [41]

Answer:

The first term is:

  • a_1=-61

Step-by-step explanation:

The arithmetic sequence is defined by

a_n=a_1+\left(n-1\right)d

where

a_1 is the first term

d is the common difference

as

the 17th term of an arithmetic sequence is 51.

i.e. a_{17}=51

so

a_n=a_1+\left(n-1\right)d

a_{17}=a_1+\left(17-1\right)d        

51=a_1+\left(17-1\right)7         ∵ n = 17, a_{17}=51 , d=7

a_1+112=51                   ∵ \left(17-1\right)\cdot \:\:7=112

a_1=-61

Therefore, the first term is:

  • a_1=-61
8 0
3 years ago
Select the correct answer. The velocity of a train relative to the ground is represented by the distance from A to B in the diag
Alina [70]
The answer is A. 21.14 m/s
8 0
3 years ago
Read 2 more answers
What would be the equation -2x+y+3=0 in y=mx+b form?
ololo11 [35]

Answer:

The answer is y = 2x - 3.

Step-by-step explanation:

Move 2x to the right side of the equation by adding it to both sides:

-2x + y + 3 = 0

<u>+ 2x             + 2x</u>

y + 3 = 2x

Then, move 3 to the right side of the equation by subtracting it form both sides:

y + 3 = 2x

<u>   - 3    - 3</u>

y = 2x - 3

8 0
3 years ago
Find the constant rate of change for each linear function and interpret its meaning
Marina CMI [18]

the slope goes by several names

• average rate of change

• rate of change

• deltaY over deltaX

• Δy over Δx

• rise over run

• gradient

• constant of proportionality

however, is the same cat wearing different costumes.

and to get it, we simply need two points off of the straight line, hmm let's use the ones in the picture below.

(\stackrel{x_1}{2}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{6}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{6}-\stackrel{y1}{4}}}{\underset{run} {\underset{x_2}{6}-\underset{x_1}{2}}}\implies \cfrac{2}{4}\implies \cfrac{1}{2}

3 0
2 years ago
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