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BabaBlast [244]
2 years ago
11

1.If I have £400 and I give 15% of the total to charity, how much does the charityreceive?​

Mathematics
1 answer:
MakcuM [25]2 years ago
5 0
£400-15% is your equation you use, but I will use the equation of part/whole =percent/100, where a is the variable for the part, w is the variable for the whole (£400) and p is the percent that we are trying to find or use (15%):
a/400 = 15/100; multiply: 400•15= 6000; then divide: 6000/100=60
So we now know that the answer to your problem is that the Charity receives £60
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Suppose you have $12,000 to invest. If part is invested at 10% and the rest at 15%, how much should be invested at each rate to
Ivahew [28]
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-0.05x=-360x=7200 12000-x=4800 $7200 at 10%=$720$4800 at 15%=$720 That is $12000 earning $1440, and that is 12%
3 0
3 years ago
Solve for x x + 47 = -23
givi [52]
X = -23 - 47 
x = -70
-70 + 47 = -23
7 0
3 years ago
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A student is taking two courses, history and math. the probability the student will pass the history course is 0.59, and the pro
natka813 [3]

Probability of passing history course = 0.59

Probability of passing math course = 0.60

Probability of passing both courses = 0.49

Probability of passing at least one = 0.59 + 0.60 - 0.49 = 0.7 ##

3 0
3 years ago
Find the indicated limit, if it exists.
kondor19780726 [428]

Answer:

d) The limit does not exist

General Formulas and Concepts:

<u>Calculus</u>

Limits

  • Right-Side Limit:                                                                                             \displaystyle  \lim_{x \to c^+} f(x)
  • Left-Side Limit:                                                                                               \displaystyle  \lim_{x \to c^-} f(x)

Limit Rule [Variable Direct Substitution]:                                                             \displaystyle \lim_{x \to c} x = c

Limit Property [Addition/Subtraction]:                                                                   \displaystyle \lim_{x \to c} [f(x) \pm g(x)] =  \lim_{x \to c} f(x) \pm \lim_{x \to c} g(x)

Step-by-step explanation:

*Note:

In order for a limit to exist, the right-side and left-side limits must equal each other.

<u>Step 1: Define</u>

<em>Identify</em>

\displaystyle f(x) = \left\{\begin{array}{ccc}5 - x,\ x < 5\\8,\ x = 5\\x + 3,\ x > 5\end{array}

<u>Step 2: Find Right-Side Limit</u>

  1. Substitute in function [Limit]:                                                                         \displaystyle  \lim_{x \to 5^+} 5 - x
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                           \displaystyle  \lim_{x \to 5^+} 5 - x = 5 - 5 = 0

<u>Step 3: Find Left-Side Limit</u>

  1. Substitute in function [Limit]:                                                                         \displaystyle  \lim_{x \to 5^-} x + 3
  2. Evaluate limit [Limit Rule - Variable Direct Substitution]:                           \displaystyle  \lim_{x \to 5^+} x + 3 = 5 + 3 = 8

∴ Since  \displaystyle \lim_{x \to 5^+} f(x) \neq \lim_{x \to 5^-} f(x)  , then  \displaystyle \lim_{x \to 5} f(x) = DNE

Topic: AP Calculus AB/BC (Calculus I/I + II)

Unit:  Limits

5 0
2 years ago
Diya spent 2/5 of her money on a dress and 1/2 of the reminder on a doll. She spent $8 more o the dress than the doll. How much
Elena L [17]

Answer:

$24

Step-by-step explanation:

2/5 — dress

3/5 — remainder

1/2 of remainder = 1/2 × 3/5 = 3/10 — doll

rewrite fraction spent on dress: 4/10

dress - doll = $8

4/10 - 3/10 = 1/10

1/10 = $8

fraction of money left = 10/10 - 4/10 - 3/10

= 3/10

amount of money left = $8 × 3

$24

8 0
3 years ago
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