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Novosadov [1.4K]

3 years ago

8

In tennis, a player must win 6 games in order to win a set. However, winning 6 games does not guarantee that the player will win

the set. If g is the number of games the player won and s is the number of sets the player won, which of the following inequalities must be true?
a. s ≤ 6g
b. s ≥ 6g
c. 6s ≤ g
d. 6s ≥ g

2 answers:

natita [175]3 years ago

5 0

Answer:

i dont really know

Step-by-step explanation:

i am doing this for the point things

Bess [88]3 years ago

4 0

Answer:

A: s ≤ 6g

Step-by-step explanation:

Had this on a test that I scored 100 on.

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The estimated daily living costs for an executive traveling to various major cities follow. The estimates include a single room

Alexandra [31]

Answer:

$\bar x = 260.1615$

$\sigma = 70.69$

The confidence interval of standard deviation is: $53.76$ to $103.25$

Step-by-step explanation:

Given

$n =20$

See attachment for the formatted data

Solving (a): The mean

This is calculated as:

$\bar x = \frac{\sum x}{n}$

So, we have:

$\bar x = \frac{242.87 +212.00 +260.93 +284.08 +194.19 +139.16 +260.76 +436.72 +355.36 +.....+250.61}{20}$

$\bar x = \frac{5203.23}{20}$

$\bar x = 260.1615$

$\bar x = 260.16$

Solving (b): The standard deviation

This is calculated as:

$\sigma = \sqrt{\frac{\sum(x - \bar x)^2}{n-1}}$

$\sigma = \sqrt{\frac{(242.87 - 260.1615)^2 +(212.00- 260.1615)^2+(260.93- 260.1615)^2+(284.08- 260.1615)^2+.....+(250.61- 260.1615)^2}{20 - 1}}$ $\sigma = \sqrt{\frac{94938.80}{19}}$

$\sigma = \sqrt{4996.78}$

$\sigma = 70.69$ --- approximated

Solving (c): 95% confidence interval of standard deviation

We have:

$c =0.95$

So:

$\alpha = 1 -c$

$\alpha = 1 -0.95$

$\alpha = 0.05$

Calculate the degree of freedom (df)

$df = n -1$

$df = 20 -1$

$df = 19$

Determine the critical value at row $df = 19$ and columns $\frac{\alpha}{2}$ and $1 -\frac{\alpha}{2}$

So, we have:

$X^2_{0.025} = 32.852$ ---- at $\frac{\alpha}{2}$

$X^2_{0.975} = 8.907$ --- at $1 -\frac{\alpha}{2}$

So, the confidence interval of the standard deviation is:

$\sigma * \sqrt{\frac{n - 1}{X^2_{\alpha/2} }$ to $\sigma * \sqrt{\frac{n - 1}{X^2_{1 -\alpha/2} }$

$70.69 * \sqrt{\frac{20 - 1}{32.852}$ to $70.69 * \sqrt{\frac{20 - 1}{8.907}$

$70.69 * \sqrt{\frac{19}{32.852}$ to $70.69 * \sqrt{\frac{19}{8.907}$

$53.76$ to $103.25$

8 0

3 years ago

Find the midpoint of the segment with the given endpoints K(-2,-4) and L(-4,6)

Ilia_Sergeevich [38]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ K(\stackrel{x_1}{-2}~,~\stackrel{y_1}{-4})\qquad L(\stackrel{x_2}{-4}~,~\stackrel{y_2}{6}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-4-2}{2}~~,~~\cfrac{6-4}{2} \right)\implies \left( \cfrac{-6}{2}~~,~~\cfrac{2}{2} \right)\implies (-3~,~1)$

8 0

3 years ago

Read 2 more answers

One solution to a quadratic equation is x= -5/3 What is true about any remaining solutions?

miv72 [106K]

Answer:

There is exactly one more real solution or there is exactly one more complex solution

Step-by-step explanation:

A quadratic equation is a polynomial of degree two

What this means is that a polynomial has two answers.

Now, from the question, we have an answer already which is a real root

Then the other answer which we do not have can take the form of two answers

It can either be a complex root or other wise be a real root

So the answer to this question is that ;

There is exactly one more real solution or there is exactly one more complex solution

3 0

3 years ago

What is the equation of the line that is parallel to the line x = -2 and passes through the point (-5, 4)?

Nastasia [14]

Answer:

The equation of the line that is parallel to the line x = -2 and passes through the point (-5, 4) is x=-5

Option A is correct.

Step-by-step explanation:

We need to find equation of the line that is parallel to the line x = -2 and passes through the point (-5, 4)

We need a line parallel to x=-2 or x+2=0 it should be of form x+k=0

We need to find k, by putting value of x=-5 as given in question the point(-5,4)

-5+k=0

k=5

So, the equation of line will be found by putting k=5:

x+k=0

x+5=0

x=-5

So, the equation of the line that is parallel to the line x = -2 and passes through the point (-5, 4) is x=-5

Option A is correct.

8 0

3 years ago

On a trip, a motorist drove 150 miles in the morning and 50 miles in the afternoon. His average rate in the morning was twice hi

Lina20 [59]

Answer:

Morning's average rate = 50 mph, and Afternoon's average rate = 25 mph.

Step-by-step explanation:

Suppose he drove 150 miles for X hours, then his average rate in the morning was (150/X) mph.

Given that he spent 5 hours in driving.

And he drove 50 miles for (5-X) hours, then his average rate in the afternoon was 50/(5-X) mph.

Given that his average rate in the morning was twice his average rate in the afternoon.

(150/x) = 2 * 50/(5-x)

150/x = 100/(5-x)

Cross multiplying terms, we get:-

150*(5-x) = 100*x

750 - 150x = 100x

750 = 100x + 150x

750 = 250x

x = 750/250 = 3.

It means he spent 3 hours in the morning and 2 hours in the afternoon.

So morning's average rate = 150/3 = 50 mph.

and afternoon's average rate = 50/(5-3) = 25 mph.

8 0

3 years ago