The following data was collected on a cheetah. It ran ½ mile in 2/3 min, ¼ mile in 1/3 min, and ¾ mile in one minute.

1 answer:

8 0

1) You can divided all of the distances by the time. The result will be 3/4 in each case, therefore it is proportional.

2) For the equation, you can multiply the time by 3/4 and it will equal the distance. You can put the values you have into a table and graph them to also show it is proportional.

3) Since there is a constant factor between the two values, they are proportional.

You might be interested in

Evaluate the expression a + b for a = 25 and b = 2

icang [17]

The answer is 25+2= 27

5 0

3 years ago

Read 2 more answers

Find the first partial derivatives of the function f(x,y,z)=4xsin(y−z)

Amanda [17]

Answer:

$f_x(x,y,z)=4\sin (y-z)$

$f_x(x,y,z)=4x\cos (y-z)$

$f_z(x,y,z)=-4x\cos (y-z)$

Step-by-step explanation:

The given function is

$f(x,y,z)=4x\sin (y-z)$

We need to find first partial derivatives of the function.

Differentiate partially w.r.t. x and y, z are constants.

$f_x(x,y,z)=4(1)\sin (y-z)$

$f_x(x,y,z)=4\sin (y-z)$

Differentiate partially w.r.t. y and x, z are constants.

$f_y(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial y}(y-z)$

$f_y(x,y,z)=4x\cos (y-z)$

Differentiate partially w.r.t. z and x, y are constants.

$f_z(x,y,z)=4x\cos (y-z)\dfrac{\partial}{\partial z}(y-z)$

$f_z(x,y,z)=4x\cos (y-z)(-1)$

$f_z(x,y,z)=-4x\cos (y-z)$

Therefore, the first partial derivatives of the function are $f_x(x,y,z)=4\sin (y-z), f_x(x,y,z)=4x\cos (y-z)\text{ and }f_z(x,y,z)=-4x\cos (y-z)$ .