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AleksandrR [38]
3 years ago
13

20 points to whoever answers the questions in picture!

Mathematics
1 answer:
Rina8888 [55]3 years ago
5 0
The unit rate is 4/5 or .8. Simply divide 4/5, and then use that to find your other answers. 3/.8=3 3/4 6 1/4* .8= 5.

4 5
3 3 3/4
5 6 1/4
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At 5:00pm the temperature read 10° above zero. At midnight it read 4 ° below zero. Find the change
larisa86 [58]
The temperature changed a total of 14° over the course of 7 hours with an average change of 2° per hour drop.
6 0
3 years ago
In combining like terms with fractions what would this be 1/2k - 3/8k =
DanielleElmas [232]

Answer:

Step-by-step explanation:

1/2k - 3/8k.....lowest common denominator is 8

4/8k - 3/8k = 1/8k <===

6 0
3 years ago
Which of the following is a result of shifting a circle with equation
ladessa [460]
The answer might be B, but realize if a circle is shifting both y and x can’t decrease.. and both cant increase at the same time.
3 0
3 years ago
Given △XPS≅△DNF, find the values of x and y.
White raven [17]

Answer:

x = 3

y = 15

Step-by-step explanation:

If △XPS ≅△DNF, their corresponding sides would be congruent. This implies that:

XP ≅ DN

PS ≅ NF

XS ≅ DF

Given that:

XP = 4y - 3

DN = 57

NF = 51

XS = 17x + 3

DF = 54

Therefore:

XP = DN

4y - 3 = 57 (Substitution)

Add 3 to both sides

4y = 57 + 3

4y = 60

Divide both sides by 4

y = 60/4

y = 15

Also,

XS = DF

17x + 3 = 54 (substitution)

Subtract 3 from each side

17x = 54 - 3

17x = 51

Divide both sides by 17

x = 51/17

x = 3

4 0
3 years ago
Help please!! How do I solve this
egoroff_w [7]
This is an exponential equation. We will solve in the following way. I do not have special symbols, functions and factors, so I work in this way
 2 on (2x) - 5 2 on x + 4=0 =>. (2 on x)2 - 5 2 on x + 4=0  We will replace expression ( 2 on x) with variable t => 2 on x=t  =. t2-5t+4=0 => This is quadratic equation and I solve this in the folowing way => t2-4t-t+4=0 =>     t(t-4) - (t-4)=0 => (t-4) (t-1)=0 => we conclude t-4=0 or t-1=0 => t'=4 and t"=1 now we will return t' => 2 on x' = 4 => 2 on x' = 2 on 2 => x'=2 we do the same with t" => 2 on x" = 1 => 2 on x' = 2 on 0 => x" = 0 ( we know that every number on 0 gives 1). Check 1: 2 on (2*2)-5*2 on 2 +4=0 =>                   2 on 4 - 5 * 4+4=0 => 16-20+4=0 =. 0=0 Identity proving solution. 
Check 2:   2 on (2*0) - 5* 2 on 0 + 4=0 => 2 on 0 - 5 * 1 + 4=0 => 
1-5+4=0 => 0=0  Identity provin solution.
5 0
3 years ago
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