Probability that the first 2 of the friends to show up to the movie are friends he has known since kindergarten but the third not is 1/10
Total friends = 10
Friends from kindergarten = 4
Probability is the chance that a given event will occur. Probability of an event lies within 0 to 1
P(E) = Favourable outcomes / Total outcomes
Probability of getting 1st friend from kindergarten = 4/10
Probability of getting 2nd friend from kindergarten = 3/9
Probability of getting 3rd friend not from kindergarten = 6/8
Since all these probabilities are independent, We can use Multiplicative identity. Thus,
Required probability is 4/10 * 3/9 * 6/8
= 1/10
Thus, Probability that the first 2 of the friends to show up to the movie are friends he has known since kindergarten but the third not is 1/10
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Using the model equation, the predicted mean score on the final given a score of <em>10 points above the class mean</em> in the mid term exam is 50.7
<u>The Least - Square Regression equation which models the relationship between midterm and final exam score is</u> :
x = 10 points ; <u>substitute the value of x = 10 into the regression equation</u> ;
γ=46.6 + 0.41(10)
γ=46.6 + 4.1
γ = 50.7
The <em>number of points above the mean</em> he'll score in the final exam is predicted to be 50.7
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The picture isn’t loading can you re do it because I don’t see it????
Answer:
12 times
Step-by-step explanation:
We can adjust the data by adding 4 to everything before we calculate the statistics. Or we can calculate the statistics on the given data and just add 4 to everything at the end. We'll get the same answer either way.
Let's sort the seven data points: 5 5 5 7 7 9 10
Those add up to 48 so the mean is 48/7 = 6.9
The one in the middle is 7 so the median = 7
The mode is the most common one, mode = 5
The range is the difference between max and min, so range = 10 - 5 = 5
In the second week we add four to everything. Since that adds four to the min and max, the range doesn't change.
Answer: mean=10.9, median=11, mode=9, range=5
