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ExtremeBDS [4]
4 years ago
13

Select the rational expression that is equivalent to the given expression below. 4/x-3

Mathematics
2 answers:
Aliun [14]4 years ago
7 0
To find the correct option we need to calculate each of the given options.
Option (1):
\frac{x+2}{x-3} /  \frac{4}{x+2} =  \frac{x+2}{x-3} *  \frac{x+2}{4} =  \frac{(x+2)^2}{4(x-3)}

Option (2):
\frac{x+2}{x-3} *  \frac{4}{x+2} =  \frac{4}{x-3}

Option (3):
\frac{x+2}{x-3} - \frac{4}{x+2} = \frac{(x+2)^2-4(x-3)}{(x-3)(x+2)}

option (4)
\frac{x+2}{x-3} + \frac{4}{x+2} = \frac{(x+2)^2+4(x-3)}{(x-3)(x+2)}


So, the correct answer is option (2)
Thepotemich [5.8K]4 years ago
7 0
The second one where there is multiplication.
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Use the quadratic formula to solve x^2 -3x - 5 = 0. Round to two decimal places.
Evgen [1.6K]

Answer:

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

x=\frac{3+\sqrt{29}}{2},\:x=\frac{3-\sqrt{29}}{2}

Step-by-step explanation:

Given the equation

x^2\:-3x\:-\:5\:=\:0

solving with the quadratic formula

\mathrm{For\:a\:quadratic\:equation\:of\:the\:form\:}ax^2+bx+c=0\mathrm{\:the\:solutions\:are\:}

x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

\mathrm{For\:}\quad a=1,\:b=-3,\:c=-5

x_{1,\:2}=\frac{-\left(-3\right)\pm \sqrt{\left(-3\right)^2-4\cdot \:1\cdot \left(-5\right)}}{2\cdot \:1}

x_{1,\:2}=\frac{-\left(-3\right)\pm \sqrt{29}}{2\cdot \:1}

separating the solutions

x_1=\frac{-\left(-3\right)+\sqrt{29}}{2\cdot \:1},\:x_2=\frac{-\left(-3\right)-\sqrt{29}}{2\cdot \:1}

solving

x=\frac{-\left(-3\right)+\sqrt{29}}{2\cdot \:\:1}

  =\frac{3+\sqrt{29}}{2\cdot \:1}

  =\frac{3+\sqrt{29}}{2}

also solving

\:x=\frac{-\left(-3\right)-\sqrt{29}}{2\cdot \:\:1}

  =\frac{3-\sqrt{29}}{2\cdot \:1}

  =\frac{3-\sqrt{29}}{2}

\mathrm{The\:solutions\:to\:the\:quadratic\:equation\:are:}

x=\frac{3+\sqrt{29}}{2},\:x=\frac{3-\sqrt{29}}{2}

7 0
3 years ago
Match each condition to the number of quadrilateral that can be constructed to fit the condition.
ss7ja [257]

one- A, C, F many- B, D, E

i just took the test and aced it, this is what  answered

8 0
3 years ago
Read 2 more answers
PLEASE HELP, I can't figure this out :(
zubka84 [21]

Answer:

WDQA

Step-by-step explanation:

Notice that angle P has two arc marks.  Look for the same marks in the other polygon: angle W has two arc marks.  So P and W are corresponding angles.

Repeat for the rest of the letters:

G → D

Y → Q

X → A

Matching each letter, the similarity statement is:

PGYX ~ WDQA

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4 years ago
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lisov135 [29]

Increasing the amount of fuel by 28 gallons from 10 to 38 increased the weight by 154 pounds from 2155 to 2309 pounds.

The increase to 52 gallons of fuel is an increase of 14 gallons from 38, which is half the previous increase of 28 gallons. Thus, we expect the increase in weight from 2309 pounds to be half the previous increase, or 154/2 = 77 pounds.

2309 + 77 = 2386 . . . pounds

We expect the airplane to weigh 2386 pounds when it is carrying 52 gallons of fuel.

5 0
3 years ago
Rewrite the function to determine whether it represents exponential growth or exponential decay
mihalych1998 [28]

Answer:

Growth.

Step-by-step explanation:

The growth factor is 1.18 ( > 1) and the exponent is > 0.

5 0
3 years ago
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