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Allushta [10]
3 years ago
9

Identify the horizontal asymptote of f(x) = quantity 2 x minus 1 over quantity x squared minus 7 x plus 3.

Mathematics
1 answer:
Rina8888 [55]3 years ago
3 0
We must recall that a horizontal asymptote is the value/s of y that the given function approaches to but never reaches. To find this in a rational function, we compare the expressions with highest degree in the numerator and denominator. There are three possible outcome when this happens.

1. if the highest degree (highest exponent) in the numerator is bigger than that of the denominator, then there won't be any horizontal asymptote.

2. if the highest degree in the denominator is bigger, then the horizontal symptote would be y = 0.

3. if they have the same highest degree, then we just get the quotient of their coefficient. 

Now, going back to our function, we have

f(x) = \frac{2x - 1}{x^{2} - 7x + 3}

From this we can see that the highest degree in the numerator is 1 (from 2x) and 2 (from x²) for the denominator. Clearly, it shows that its denominator has a higher degree. And from our discussion, we can conclude that the horizontal asymptote would be y = 0.

Answer: y = 0
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Read 2 more answers
1. Factor the trinomial: x2 - 7x - 8
telo118 [61]

1. A

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2. A

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7 0
3 years ago
Consider the line shown on the graph. Enter the
Semenov [28]

<h2>Solution -</h2>

From the graph, we concluded that line passes through the points (0, 3) and (1, 4) respectively.

So, slope of the line (m) passing through the points (a, b) and (c, d) is

m = d - b/ c - a

<h3>So, on substituting the values, we get </h3>

m = 4 - 3 / 1 - 0 = 1/1 = 1

Also, line makes an intercept of 3 units in positive direction of y - axis.

So, c = 3

<h3>So, Equation of line is given by</h3>

y = mx + c

y = 1 × x + 3

<h3>y = x + 3</h3>

<h3>Alternative Method :-</h3>

We know, Equation of line passing through the points (a,b) and (c, d) is given by

y - b = d - b / c - a (x - a)

<h3>Here,</h3>

a = 0

b = 3

c = 1

d = 4

<h3>So, on substituting these values in above result, we get :-</h3>

y - 3 = 4 - 3 /1 - 0 ( x - 0 )

y - 3 = 1/1 ( x - 0 )

y - 3 = x

<h3>y = x + 3</h3>

<h3>Different forms of equations of a straight line :-</h3>

1. Equations of horizontal and vertical lines

Equation of line parallel to x - axis passes through the point (a, b) is y = b.

Equation of line parallel to y - axis passes through the point (a, b) is x = a.

<h3>2. Point-slope form equation of line</h3>

Equation of line passing through the point (a, b) having slope m isy - b = m(x - a)

<h3>3. Slope-intercept form equation of line</h3>

Equation of line which makes an intercept of c units on y axis and having slope m is y = mx + c.

<h3>4. Intercept Form of Line</h3>

Equation of line which makes an intercept of a and b units on x - axis and y axis respectively is x/a + y/b = 1.

<h3>5. Normal form of Line</h3>

Equation of line which is at a distance of p units from the origin and perpendicular makes an angle B with the positive X-axis is x cosB + y sinB = p.

<h2 />

8 0
2 years ago
write the equation of the line that is perpendicular to the line y=-1/5x+9 and passes through the point (-2,-2)
OLEGan [10]

Answer:y=5x+8

Step-by-step explanation: the perpendicular slope is going to be the negative reciprocal of your given slope. In this case the perpendicular line has a slope of 5, because u flip -1/5 to make -5 and u negate -5 to make 5. This perpendicular slope passes through (-2,-2) and u find the y intercept like this: -2=(5(-2))+b. Therefore the y intercept is 8 and the perpendicular slope is y=5x+8

4 0
4 years ago
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