Answer:
Height of the object is 68.6 cm.
Step-by-step explanation:
The height of the object can be determined by:
= 
From the given question;
object distance from pinhole = 3.6 m = 360 cm
image distance from pinhole = 4.2 cm
height of image = 0.8 cm
So that;
= 
⇒ object height = 
= 
= 68.571
object height = 68.6 cm
Thus, the height of the object is 68.6 cm.
Answer:
Where is the photo?
Step-by-step explanation:
Answer:
3x/4
Step-by-step explanation:
that's what I found. It would be better if u had more details in your question.
Do you want 5 and 6 or just 5? 5 is kind of neat.
44.5% = 0.445
4/9 = 0.4444444
You have enough information to put the numbers in order.
0.44 is the smallest number.
0.44444444.... is the next smallest number
0.4445 is bigger than the number above. 5 is in the ten thousandths place. that is bigger than 4 in the thousands place of 4/9
Finally the largest number of all is 0.445 for the same reason given above.
Six
5/12 = 0.416666
0.4
42% = 42/100 = 0.42
0.416
0.4 is the smallest number
0.416 is the next smallest number
0.41666666 is bigger than 0.416 because you are adding a bunch of 6s onto the decimal place.
The largest one is 0.42. You can put these into your calculator to verify the results. For example, 0.42 - 0.4166666 = 0.003344. Any result more than 0 will show that the first number is bigger than the second.
Answer:
Option E is correct.
The expected number of meals expected to be served on Wednesday in week 5 = 74.2
Step-by-step Explanation:
We will use the data from the four weeks to obtain the fraction of total days that number of meals served at lunch on a Wednesday take and then subsequently check the expected number of meals served at lunch the next Wednesday.
Week
Day 1 2 3 4 | Total
Sunday 40 35 39 43 | 157
Monday 54 55 51 59 | 219
Tuesday 61 60 65 64 | 250
Wednesday 72 77 78 69 | 296
Thursday 89 80 81 79 | 329
Friday 91 90 99 95 | 375
Saturday 80 82 81 83 | 326
Total number of meals served at lunch over the 4 weeks = (157+219+250+296+329+375+326) = 1952
Total number of meals served at lunch on Wednesdays over the 4 weeks = 296
Fraction of total number of meals served at lunch over four weeks that were served on Wednesdays = (296/1952) = 0.1516393443
Total number of meals expected to be served in week 5 = 490
Number of meals expected to be served on Wednesday in week 5 = 0.1516393443 × 490 = 74.3
Checking the options,
74.3 ≈ 74.2
Hence, the expected number of meals expected to be served on Wednesday in week 5 = 74.2
Hope this Helps!!!
