Hi there! The answer is (1/2)
I suppose you mean the slope of a line that is parallel to y = (1/2)x + 3.
This equation is written in slope-intercept form, which means that the number in front of x represents the slope of the line. The other number represents the y-intercept.
A line that is parallel to another line, will be a line with the same slope. Since the slope of y = (1/2)x + 3 is (1/2), the slope of a line parallel to this line is (1/2) as well.
~ Hope this helps you!
Step-by-step explanation:
I assume that "ground" is at 0 ft height. which is in an actual scenario not airways the case.
y = -16x² + 64x + 89
shows us that the tower is 89 ft tall (the result for x = 0, at the start).
anyway, if the original assumption is correct, then we need to solve
0 = -16x² + 64x + 89
the general solution for such a quadratic equation is
x = (-b ± sqrt(b² - 4ac))/)2a)
in our case
a = -16
b = 64
c = 89
x = (-64 ± sqrt(64² - 4×-16×89))/(2×-16) =
= (-64 ± sqrt(4096 + 5696))/-32 =
= (-64 ± sqrt(9792))/-32
x1 = (-64 + 98.95453501...)/-32 = -1.092329219... s
x2 = (-64 - 98.95453501...)/-32 = 5.092329219... s
the negative solution for time is but useful here (it would be the time calculated back to ground at the start).
so, x2 is our solution.
the rocket hits the ground after about 5.09 seconds.
Answer:
this is impossible
Step-by-step explanation:
Answer:
DE ≅ DG
Step-by-step explanation:
Answer:
No
Step-by-step explanation:
