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otez555 [7]
3 years ago
12

5/8m-3/8=1/2m+7/8 how do you solve this. variables on both sides. STEP BY STEP PLEASE!!!!!!!!!

Mathematics
2 answers:
Jlenok [28]3 years ago
6 0
Watch this and you will be alright .
https://youtu.be/f15zA0PhSek
Lynna [10]3 years ago
6 0

Combine like terms:  (5/8)m - (1/2)m = 7/8 + 3/8 = 10/8

                                        (1/8)m = 10/8

Now mult both sides by 8 to remove 8 from the denominators:

                                             m = 10

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Assoli18 [71]
It is 22 my guy because i think it is 22
3 0
3 years ago
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How do you do this question?
Sergeeva-Olga [200]

Answer:

V = 2000r³/3

Step-by-step explanation:

We know that the base is a circular disk, so it creates a circle on the xy plane. It would be in the form x² + y² = r². In other words x² + y² = (5r)². Let's isolate y in this equation now:

x² + y² = (5r)²,

x² + y² = 25r²,

y² = 25r² - x²,

y = √25r² - x² ---- (1)

Now remember that parallel cross sections perpendicular to the base are squares. Therefore Area = length^2. The length will then be = 2√25r² - x² --- (2). Now we can evaluate the integral from -5r to 5r, of [ 2√25r² - x² ]² dx.

\int _{-5r}^{5r}\:\left[\:2\sqrt{\left(25r^2\:-\:x^2\right)}\:\right]\:^2\:dx\\=\int _{-5r}^{5r}4\left(25r^2-x^2\right)dx\\\\= 4\cdot \int _{-5r}^{5r}25r^2-x^2dx\\\\= 4\left(\int _{-5r}^{5r}25r^2dx-\int _{-5r}^{5r}x^2dx\right)\\\\= 4\left(250r^3-\frac{250r^3}{3}\right)\\\\= 4\cdot \frac{500r^3}{3}\\\\= \frac{2000r^3}{3}

As you can see, your exact solution would be, V = 2000r³/3. Hope that helps!

3 0
3 years ago
Please help. 50 Points.
Ronch [10]

Answer:

0.8745.

Step-by-step explanation:

P(success) = 0.09 and P(failure) = 1 - 0.09 = 0.91.

P( at least 6 failures) = P( less than 2 successes)

= 7C0 (0.09)^0 (0.91)^7 + 7C1 (0.09)(0.91)^6

=  0.5168 + 0.3577

= 0.8745.

8 0
3 years ago
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Can anyone solve these? Thanks.
lisabon 2012 [21]
It won't let me see the picture sorry
3 0
3 years ago
4 Pencils and 2 rulers cost $8. 2 pencils and 4 rulers cost $10. Find the cost of 3 rulers and 3 pencils
Marat540 [252]

Answer:

4 pencil & 2 ruler = $8

2 pencil & 4 ruler = $10

let the no. of Pencil be X and no. of ruler be Y

4x + 2y = 8

2x + 4y= 10

solving the equation by elimination method,

multiplying eq 2 with 2

4x + 2y = 8

4x + 8y = 20

subtracting,

- 6 y = -12

y = 2

2x + 4(2)= 10

2x + 8 = 10

2x = 10 - 8

2x = 2

x = 1

Cost of 3 ruler + 3 pencil

= 3(1) + 3(2)

= 3 + 6

= 9

<h2 /><h2>= $9</h2>
4 0
2 years ago
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