Answer:
y = 4(x + 11)² - 484
Step-by-step explanation:
y = 4x² + 88x
factor the expression
y = 4(x² + 22x)
complete the square
y + ? = 4(x² + 22x + ?)
y + ? = 4(x² + 22x + 121)
add 4 • 121 to the left side
y + 4 • 121 = 4(x² + 22x + 121)
multiply
y + 484 = 4(x² + 22x + 121)
y + 484 = 4(x + 11)²
subtract both sides by 484
y = 4(x + 11)² - 484
The tower is 61.65 meters tall.
<u>SOLUTION:
</u>
Given that, a pole that is 2.5 m tall casts a shadow that is 1.47 m long.
At the same time, a nearby tower casts a shadow that is 36.25 m long.
We have to find height of the tower.
Now, we know that,

Then, (let it be) n meter tall
36.25 long shadow
So, by cross multiplication method,

This can be written as,

Cross multiplications steps: (To find Single Variable)
- Multiply the numerator of the left-hand fraction by the denominator of the right-hand fraction.
- Multiply the numerator of the right-hand fraction by the denominator of the left-hand fraction.
- Set the two products equal to each other.
- Solve for the variable.
Hello,
Answer:
The last graph (2;3)
Step-by-step explanation:
2x + 3y = 12
2x – 3y = 0
2x + 3y = 12
2x = 3y
3y + 3y = 12 ⇔ 6y = 12 ⇔ y = 12/6 = 2
2x + 3 × 2 = 12 ⇔ 2x + 6 = 12 ⇔ 2x = 6 ⇔ x = 6/2 = 3
Answer:
Step-by-step explanation:
The answer is B.
Use the sum-product pattern
2+3−3−9
Common factor from the two pairs
2+3−3−9x2+3x−3x−9
(+3)−3(+3)
Rewrite in factored form
(+3)−3(+3)
Solution:
(−3)(+3)
‘Hope it Helps!
I believe the equation is
![4 \sqrt[4]{2x} + 6 \sqrt[4]{2x}](https://tex.z-dn.net/?f=4%20%5Csqrt%5B4%5D%7B2x%7D%20%2B%206%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
In this case, you would simplify it by adding them together.
![4 \sqrt[4]{2x} + 6 \sqrt[4]{2x}](https://tex.z-dn.net/?f=4%20%5Csqrt%5B4%5D%7B2x%7D%20%2B%206%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
=
![10 \sqrt[4]{2x}](https://tex.z-dn.net/?f=10%20%20%5Csqrt%5B4%5D%7B2x%7D%20)
And can even be changed to an exponential equation: