Answer:
c = 30.56 to the nearest hundredth
Step-by-step explanation:
87 = 9/5 c + 32
87 - 32 = 9/5 c
9/5 c = 55
multiply both sides by 5/9:
c = 55*5 / 9
c = 30.56.
Root 3 /sin 20 - 1/cos 20
= (root3 cos 20 - sin 20 )/ (sin 20 cos 20)
(multiplying and dividing by 2)
= 2* (root3/2 cos 20 -1/2 sin 20)/ (sin 20 cos 20)
now sin 20 cos 20 = (2 sin 20 cos 20)/2 = (sin 40)/2
and writing root3/2 = sin 60, 1/2 = cos 60
= 2* (sin 60 cos 20 - cos 60 sin 20)/ (sin 40)/2
= 4* (sin (60-20))/sin 40
= 4* (sin 40)/sin 40
=4
Ask if any doubt in any step :)
<span> FOIL is a mnemonic rule for multiplying binomial (that is, two-term) algebraic expressions. </span>
<span>FOIL abbreviates the sequence "First, Outside, Inside, Last"; it's a way of remembering that the product is the sum of the products of those four combinations of terms. </span>
<span>For instance, if we multiply the two expressions </span>
<span>(x + 1) (x + 2) </span>
<span>then the result is the sum of these four products: </span>
<span>x times x (the First terms of each expression) </span>
<span>x times 2 (the Outside pair of terms) </span>
<span>1 times x (the Inside pair of terms) </span>
<span>1 times 2 (the Last terms of each expression) </span>
<span>and so </span>
<span>(x + 1) (x + 2) = x^2 + 2x + 1x + 2 = x^2 + 3x + 2 </span>
<span>[where the ^ is the usual way we indicate exponents here in Answers, because they're hard to represent in an online text environment]. </span>
<span>Now, compare this to multiplying a pair of two-digit integers: </span>
<span>37 × 43 </span>
<span>= (30 × 40) + (30 × 3) + (7 × 40) + (7 × 3) </span>
<span>= 1200 + 90 + 280 + 21 </span>
<span>= 1591 </span>
<span>The reason the two processes resemble each other is that multiplication is multiplication; the difference in the ways we represent the factors doesn't make it a fundamentally different operation. </span>
Answer:
The answer is C.
Step-by-step explanation:
Given the line segment ST. we have to give the instruction to construct the perpendicular bisector of line ST.
So to construct the perpendicular bisector of line our first step is to place the compass at one end of line and then adjust the compass more than half of line segment and draw the arc on each side of segment.
After that Keeping the same compass width, draw arcs from other end of line. Place scale where the arcs intersect, and draw the line segment.
So, the correct match is option C ) Place the compass point on point S and open the compass so that the pencil point is on the segment, but closer to point T than to point S. Draw an arc on each side of segment.
