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soldier1979 [14.2K]
3 years ago
5

What it the x and y intercept of y=2x^2+3x+1

Mathematics
1 answer:
babunello [35]3 years ago
5 0

x = -1

y = 1

To find this, input the equation into a graphing calculator, whether online or an actual one, and you have two options:

1 - Search for the points in which the line crosses the x and or y axis.

2 - Hit 2nd Graph to access the table and find when x and y equal zero.

Hope this helps!

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ΔMNP is an isosceles triangle with MN ≈NP. If ∠ M = 3x + 1 and ∠ N = x - 11. What is the measure of ∠P?
s2008m [1.1K]

Start with an equation summing all the angles in this triangle:

180 = <M + <N + <P

we are given <M and <N but not <P. But, since MN=NP, the angle <P is the same as the angle <M (isosceles, make a drawing to see). So

180 = 2<M + <N

180 = 2(3x+1) + x-11

180 = 7x - 9

x = 27

<P = 3*27+1 = 82 degrees

4 0
3 years ago
Camille shaded 12/25 of a model. Write the decimal that represents the shaded portion of the model.
deff fn [24]

Answer: 12/25 is 0.48

because 12 divided into 25 equals 0.48

Step-by-step explanation:I’m sorry if I answered it too late

7 0
3 years ago
Find the two square roots of 9/4?
GaryK [48]

Answer: 0.75

Step-by-step explanation:

3 0
3 years ago
1....1/4 y + 1 1/2 + 2-1 3/4 y -12<br><br> 2....5=1/5x-3<br><br> 3....1/2 h + 1 from 3/4 h +4
Tanya [424]
1)  (-1 1/2)(y)-8 1/2
2)   x=40

 
7 0
3 years ago
You used p minutes one month on your cell phone. The next month you used 75 fewer minutes. Simplify the expression.
Anestetic [448]
Hi there!

Let's assume that one month is represented by the variable 'm', the amount of minutes you started with is 's', and minutes you spent is 'p'.

So, one month can be represented as 'm=s-p'.

The next month is a bit more tricky. This will incorporate 75 less minutes into the equation. 'm=s-75' can be used to represent this, as we assume that you didn't use any minutes in the first month, and that p=75 in this case.

If you found this especially helpful, I'd appreciate if you'd vote me Brainliest for your answer. I want to be able to assist more users one-on-one, as well as to move up in rank! :)
5 0
4 years ago
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