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Lady_Fox [76]
3 years ago
10

The Best Theme Park sold 130 tickets in an hour and made $5,300 from ticket sales. An adult ticket sells for $50.00. A child tic

ket sells for $20.00. Let x = the number of adult tickets and y = the number of child tickets. The solution to the system is the coordinate (90, 40). How many adult tickets were purchased that hour?
Mathematics
2 answers:
lilavasa [31]3 years ago
8 0
The solution to the system is (90,40)....x = adults and y = child's...so x = 90 (there were 90 adult tickers) and y = 40 (there were 40 child tickets)...u already had the answer right in front of you
ella [17]3 years ago
7 0
The answer is 40 I think
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the angle is 165

 so area = 165/360 x 113.04

area = 51.8 in^2

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4 years ago
Are there less than 1 million, exactly 1 million, or greater than 1 million milligrams in 1 kilogram? Explain how you know
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It is exactly one million milligrams
5 0
3 years ago
Read 2 more answers
The diagram shows part of a number line.Two of the fractions are not complete. Write the missing numerator in each box
Tcecarenko [31]
The first numerator is 3 and the second is 17 not 2
4 0
3 years ago
Help brainliest if right
kondor19780726 [428]

Answer:

y = 1x + 7

Step-by-step explanation:

<u>The equation formula for this scenario is y = mx + b</u>

m = slope

b = y-intercept

To find the slope, pick two points. I picked (2,9) and (4,11).

Subtract 11 from 9, you'll get 2.

Subtract 4 from 2, you'll get 2.

2/2 equals 1.     The slope (m) = 1

To find the b, y-intercept, plot the points on a graph and see if the linear line across the y-intercept.  For this case, the y-intercept is 7.

The equation is:  y = 1x + 7

3 0
3 years ago
The state education commission wants to estimate the fraction of tenth grade students that have reading skills at or below the e
marusya05 [52]

Answer:

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

\hat p =\frac{955-812}{955}= 0.150

0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131

0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169

And the 90% confidence interval would be given (0.131;0.169).

Step-by-step explanation:

We have the following info given:

n= 955 represent the sampel size slected

x = 812 number of students who read above the eighth grade level

The estimation for the proportion of tenth graders reading at or below the eighth grade level is given by:

\hat p =\frac{955-812}{955}= 0.150

The confidence interval for the proportion  would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 90% confidence interval the significance is \alpha=1-0.9=0.1 and \alpha/2=0.05, with that value we can find the quantile required for the interval in the normal standard distribution and we got.

z_{\alpha/2}=1.64

And replacing into the confidence interval formula we got:

0.150 - 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.131

0.150 + 1.64 \sqrt{\frac{0.150(1-0.150)}{955}}=0.169

And the 90% confidence interval would be given (0.131;0.169).

8 0
3 years ago
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