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2 years ago

Can someone tell me what are the independent and dependent variables in this picture

Mathematics

2 answers:

creativ13 [48]2 years ago

8 0

I dont know am very sorry?

Mumz [18]2 years ago

7 0

X is independent and Y is dependent

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If $17,800 is invested at an interest rate of 8% per year, find the value of the investment at the end of 5 years for the follow

marta [7]

Answer:

7120

Step-by-step explanation:

6 0

2 years ago

Difference between mafic intermediate and felsic magmas

Inga [223]

Both are indicators of the chemical composition of silicate minerals, magmas and rocks.

Mafic is used for silicate minerals, magmas and rocks that are composed of heavier elements, like magnesium, iron, calcium and sodium. They are dark and have high specific gravities.

<span>Opposite to the this, felsic silicate minerals, magmas and rocks in their composition have less from these heavy elements. They are composed from silicon, oxygen, aluminium and potassium, are light in color and have lower specific gravities.</span>

8 0

3 years ago

I need help....................

inysia [295]

10-200

12-240

15-300

21-420

3 0

2 years ago

A trapezoid has bases of lengths 13 cm and 17 cm. The

Vedmedyk [2.9K]

Answer:

135 cm²

Step-by-step explanation:

The area (A) of a trapezoid is calculated as

A = $\frac{1}{2}$ h(a + b)

where h is the height and a, b the parallel bases

Here h = 9, a = 13 and b = 17 , thus

A = $\frac{1}{2}$ × 9 × (13 + 17)

= 0.5 × 9 × 30

= 135 cm²

3 0

2 years ago

Given the position of the particle, what the position(s) of the particle when it’s at rest

choli [55]

The position function of a particle is given by:

$X\mleft(t\mright)=\frac{2}{3}t^3-\frac{9}{2}t^2-18t$

The velocity function is the derivative of the position:

$\begin{gathered} V(t)=\frac{2}{3}(3t^2)-\frac{9}{2}(2t)-18 \\ \text{Simplifying:} \\ V(t)=2t^2-9t-18 \end{gathered}$

The particle will be at rest when the velocity is 0, thus we solve the equation:

$2t^2-9t-18=0$

The coefficients of this equation are: a = 2, b = -9, c = -18

Solve by using the formula:

$t=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}$

Substituting:

$\begin{gathered} t=\frac{9\pm\sqrt[]{81-4(2)(-18)}}{2(2)} \\ t=\frac{9\pm\sqrt[]{81+144}}{4} \\ t=\frac{9\pm\sqrt[]{225}}{4} \\ t=\frac{9\pm15}{4} \end{gathered}$

We have two possible answers:

$\begin{gathered} t=\frac{9+15}{4}=6 \\ t=\frac{9-15}{4}=-\frac{3}{2} \end{gathered}$

We only accept the positive answer because the time cannot be negative.

Now calculate the position for t = 6:

$undefined$

6 0

1 year ago