Given:
The equation is:
To find:
The error in the given equation and correct it.
Solution:
We have,
Taking left-hand side, we get
![[\because a^2-b^2=(a-b)(a+b)]](https://tex.z-dn.net/?f=%5B%5Cbecause%20a%5E2-b%5E2%3D%28a-b%29%28a%2Bb%29%5D)
![[\because (ab)^x=a^xb^x]](https://tex.z-dn.net/?f=%5B%5Cbecause%20%28ab%29%5Ex%3Da%5Exb%5Ex%5D)
It is not equal to right-hand side 
. In the right hand side, there must be a negative sign instead of positive sign.
Therefore, 
.
Answer:
(-7, -3) (Answer A)
Step-by-step explanation:
We start with the point (-7, -3). The x-coordinate does not change at all if we reflect this point across the x-axis. Whereas the y-value of (-7, -3) is -3, we end up with +3 after this reflection. The desired image is (-7, +3) (Answer A)
Answer: p/4
Step-by-step explanation: you divide the whole perimeter by 4 because a square has 4 sides
