The answer is )A
OK THANK YOU I HOPE THIS HOPED
Check the picture below.
a)
so the perimeter will include "part" of the circumference of the green circle, and it will include "part" of the red encircled section, plus the endpoints where the pathway ends.
the endpoints, are just 2 meters long, as you can see 2+15+2 is 19, or the radius of the "outer radius".
let's find the circumference of the green circle, and then subtract the arc of that sector that's not part of the perimeter.
and then let's get the circumference of the red encircled section, and also subtract the arc of that sector, and then we add the endpoints and that's the perimeter.


b)
we do about the same here as well, we get the full area of the red encircled area, and then subtract the sector with 135°, and then subtract the sector of the green circle that is 360° - 135°, or 225°, the part that wasn't included in the previous subtraction.

Answer:
f(2)=5
f(5)=33
Step-by-step explanation:
The given formula, that recursively defines the sequence is

When n=1, we obtain;

When n=2, we get:

When n=3,

When n=4

When n=5,

Answer:
60% decrease
Step-by-step explanation:
To work out percentage change you takeaway the original number by the new number (New number-Original number) in this case 24-60=(-36), then divide the decreased amount by the original number and multiply the answer by 100 (Decrease amount ÷ Original number x 100) for this question you'd do (-36)÷60=(-0.6) then (-0.6)x100=(-60).
The minus shows its a decrease in percentage by 60%
(I hope this helps srry if it doesn't make sense)