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3 years ago

How to get rid of a negative exponent in a fraction?

1 answer:

6 0

So let’s say we have (3/2)^-2. We know that any negative exponent means we have to put that number under 1, with a positive exponent:

1 / (3/2)^2

There’s also another thing we can do. There’s a rule in maths that says we can get the positive exponent if we just flip the fraction, so we get:

(3/2)^-2

Flip it:

(2/3)^2

It would be the same as 1 / (3/2)^2, since that would be 1/1 / 9/4, resulting in 4/9 (multiply inner part with inner part (9*1) and that goes under, and outer with outer (4*1) and that goes over). (2/3)^2 is also 4/9, so both ways are valid.

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After 3 years, Remington earned $390 in simple interest from a CD into which he initially deposited $4000. What was the annual i

olganol [36]

R=I/pt
R=(390÷(4,000×3))×100
R=3.25%

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3 years ago

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A vine in mr. Jackson’s garden is 3.6 feet long. When it is measured agian, it is 2.1 times as long. How long is the vine

Ket [755]

Take note that the vine was 3.6 ft and now it is 2.1 times as long.

So since is it 2.1 times as long it will be multiplied by 3.6.

3.6(2.1)= 7.56

So it is 7.56 ft long, rounded it is 7.6 ft

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3 years ago

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Find the slope of the line. Will give brainiest if correct.

tia_tia [17]

Answer:

1,2

Step-by-step explanation:

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3 years ago

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Work in the five days?

Ghella [55]

Answer:

9.3

Step-by-step explanation:

last week she worked 45.6 hours. since 40 hours is the limit for normal working hours, she worked 45.6-40 = 5.6 hours overtime.

this week she worked 9.7+8.3+8+9.1+8.6 hours = 43.7 hours.

she worked therefore 43.7-40 = 3.7 hours overtime.

so, in total of the two weeks, she worked 5.6+3.7 = 9.3 hours overtime.

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3 years ago

20 feet of ribbon, cutting ribbon into 7 1/2 inches or 6 3/4 inch lengths to make bracelets. Write an algebraic expression that

IRINA_888 [86]

ANSWER:

The algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$ and the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

SOLUTION:

Given, 20 feet of ribbon, cutting ribbon into $7\frac{1}{2}$ inches or $6\frac{3}{4}$ inch lengths to make bracelets.

Let us convert the mixed fraction to improper fractions.

$7 \frac{1}{2}=\frac{7 \times 2+1}{2}=\frac{15}{2} \text { and } 6 \frac{3}{4}=\frac{6 \times 4+3}{4}=\frac{27}{4}$

Let, the length of bracelets can be made be “x”

First we have to remove the excess length of ribbon and then we have to divide the remaining with length of bracelet we want.

$\text { number of ribbons }=\frac{\text { length of ribbon-excess ribbon.}}{\text {length of bracelet}}$

$\left.=\frac{20 \text { feet }-\left\{\frac{20 \text { feep }}{x}\right.}{x} \text { [we know that, }\{x\} \text { is fractional part of } x\right$ ]

So, the algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$

Now, let us find the algebraic expression for feet of ribbon to make 100 ribbons.

We have 100 bracelets of length x, then total length = 100 × x

length of ribbon = 100x inches

$\begin{array}{l}{=100 \mathrm{x} \times \frac{1}{12} \text { feet }} \\\\ {=\frac{25 x}{3} \text { feet }}\end{array}$

So, the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

Hence, the algebraic expression for number of ribbons is $\frac{20 \text { feet }-\left\{\frac{20 \text { feet }}{x}\right\}}{x}$ and the algebraic expression for length of ribbon is $\frac{25 x}{3} \text { feet }$

5 0

3 years ago