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NARA [144]
3 years ago
7

If an object on Jupiter has a mass of 25 kg, and the acceleration due to gravity is 24.5 meters per second per second, what is t

he object's weight?
Mathematics
1 answer:
WITCHER [35]3 years ago
8 0

Answer:

g=24.5m/s2

Step-by-step explanation:

hope i helped

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Danessa needs to compare the area of one large circle with a diameter of 8 to the total area of 2 smaller circles with a diamete
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The answer is: 1, 2, and 6

Step-by-step explanation:

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3 years ago
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Translate this sentence into an equation.
ElenaW [278]

Answer:

The product of Victor's age and 7 is 84 in equation form is 7v=84

Step-by-step explanation:

Let v be the  Victor's age.

We are supposed to Translate this sentence into an equation

The product of Victor's age and 7 is 84

Victor's age = v

Product of victor's age and 7 =7 \times v

We are given that their product is 84

So,7 \times v =84

Hence The product of Victor's age and 7 is 84 in equation form is 7v=84

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3 years ago
A remote-controlled plane is flying 16.5 meters above the ground. The plane dives 8 meters
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Answer:

B

Step-by-step explanation:

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3 years ago
PLEASE HELP!<br><br><br> put integers in order least to greatest 3, -2, -5.
stiks02 [169]

Answer:

-5 -2 3


The further down you go, the less it will be. so -5 would be the least, -2 would be in the middle and the greatest would be 3 because its positive



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5 0
4 years ago
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Two standardized​ tests, a and​ b, use very different scales of scores. the formula upper a equals 40 times upper b plus 50a=40×
Leona [35]
Adding (or subtracting) a constant to every data value adds (or subtracts) the same constant to measures of position such as center,percentiles, max or min.

Its shape and spread such as range, IQR, standard deviation remain unchanged.
When we multiply (or divide) all the data values by any constant, all measures of position (such as the mean, median, and percentiles) and measures of spread (such as the range, the IQR, and the standard deviation) are multiplied (or divided) by that same constant.
Part A:

The lowest score is a measure of location, so both addition and multiplying the lowest score of test B by 40 and adding 50 to the result will affect the lowest score of test A.

Thus, the lowest score of test A is given by 40(21) + 50 = 890

Therefore, the lowest score of test A is 890.



Part B:

The mean score is a measure of location, so both addition and multiplying the mean score of test B by 40 and adding 50 to the result will affect the lowest score of test A.

Thus, the mean score of test A is given by 40(29) + 50 = 1,210

Therefore, the mean score of test A is 890.



Part C:

The standard deviation is a measure of spread, so multiplying the standard deviation of test B by 40 will affect the standard deviation but adding 50 to the result will not affect the standard deviation of test A.

Thus, the standard deviation of test A is given by 40(2) = 80

Therefore, the standard deviation of test A is 80.



Part D

The Q3 score is a measure of location, so both addition and multiplying the Q3 score of test B by 40 and adding 50 to the result will affect the Q3 score of test A.

Thus, the Q3 score of test A is given by 40(28) + 50 = 1,170

Therefore, the Q3 score of test a is 1,170.



Part E:

The median score is a measure of location, so both addition and multiplying the median score of test B by 40 and adding 50 to the result will affect the median score of test A.

Thus, the median score of test A is given by 40(26) + 50 = 1,090

Therefore, the median score of test A is 1,090.



Part F:

The IQR is a measure of spread, so multiplying the IQR of test B by 40 will affect the IQR but adding 50 to the result will not affect the IQR of test A.

Thus, the IQR of test A is given by 40(6) = 240

Therefore, the IQR of test A is 240.
6 0
3 years ago
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