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3 years ago

7

If an object on Jupiter has a mass of 25 kg, and the acceleration due to gravity is 24.5 meters per second per second, what is t

he object's weight?

1 answer:

WITCHER [35]3 years ago

8 0

Answer:

g=24.5m/s2

Step-by-step explanation:

hope i helped

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The polynomial function f(x) = 3x5 - 2x2 + 7x models the motion of a roller coaster. The roots of the function represent when

sladkih [1.3K]

Answer:

0, ±1, ±7,±1/3, and ±7/3

Step-by-step explanation:

In the function:

3x^5 - 2x² + 7x

x can be extracted as the greatest common factor, as follows:

x(3x^4 - 2x + 7)

then, zero is one root of the function.

According to Rational Root Theorem:

possible rational roots = factors of the constant/factors of the leading coefficient

For this case, factors of the constant (7) are: ±1 and ±7

For this case, factors of the leading coefficient (3) are: ±1 and ±3

Then:

possible rational roots = ±1/±1, ±7/±1, ±1/±3 and ±7/±3. Simplifying: ±1, ±7,±1/3, and ±7/3

7 0

2 years ago

Use green's theorem to compute the area inside the ellipse x252+y2172=1. use the fact that the area can be written as ∬ddxdy=12∫

Pavel [41]

The area of the ellipse $E$ is given by

$\displaystyle\iint_E\mathrm dA=\iint_E\mathrm dx\,\mathrm dy$

To use Green's theorem, which says

$\displaystyle\int_{\partial E}L\,\mathrm dx+M\,\mathrm dy=\iint_E\left(\frac{\partial M}{\partial x}-\frac{\partial L}{\partial y}\right)\,\mathrm dx\,\mathrm dy$

( $\partial E$ denotes the boundary of $E$ ), we want to find $M(x,y)$ and $L(x,y)$ such that

$\dfrac{\partial M}{\partial x}-\dfrac{\partial L}{\partial y}=1$

and then we would simply compute the line integral. As the hint suggests, we can pick

$\begin{cases}M(x,y)=\dfrac x2\\\\L(x,y)=-\dfrac y2\end{cases}\implies\begin{cases}\dfrac{\partial M}{\partial x}=\dfrac12\\\\\dfrac{\partial L}{\partial y}=-\dfrac12\end{cases}\implies\dfrac{\partial M}{\partial x}-\dfrac{\partial L}{\partial y}=1$

The line integral is then

$\displaystyle\frac12\int_{\partial E}-y\,\mathrm dx+x\,\mathrm dy$

We parameterize the boundary by

$\begin{cases}x(t)=5\cos t\\y(t)=17\sin t\end{cases}$

with $0\le t\le2\pi$ . Then the integral is

$\displaystyle\frac12\int_0^{2\pi}(-17\sin t(-5\sin t)+5\cos t(17\cos t))\,\mathrm dt$

$=\displaystyle\frac{85}2\int_0^{2\pi}\sin^2t+\cos^2t\,\mathrm dt=\frac{85}2\int_0^{2\pi}\mathrm dt=85\pi$

###

Notice that $x^{2/3}+y^{2/3}=4^{2/3}$ kind of resembles the equation for a circle with radius 4, $x^2+y^2=4^2$ . We can change coordinates to what you might call "pseudo-polar":

$\begin{cases}x(t)=4\cos^3t\\y(t)=4\sin^3t\end{cases}$

which gives

$x(t)^{2/3}+y(t)^{2/3}=(4\cos^3t)^{2/3}+(4\sin^3t)^{2/3}=4^{2/3}(\cos^2t+\sin^2t)=4^{2/3}$

as needed. Then with $0\le t\le2\pi$ , we compute the area via Green's theorem using the same setup as before:

$\displaystyle\iint_E\mathrm dx\,\mathrm dy=\frac12\int_0^{2\pi}(-4\sin^3t(12\cos^2t(-\sin t))+4\cos^3t(12\sin^2t\cos t))\,\mathrm dt$

$=\displaystyle24\int_0^{2\pi}(\sin^4t\cos^2t+\cos^4t\sin^2t)\,\mathrm dt$

$=\displaystyle24\int_0^{2\pi}\sin^2t\cos^2t\,\mathrm dt$

$=\displaystyle6\int_0^{2\pi}(1-\cos2t)(1+\cos2t)\,\mathrm dt$

$=\displaystyle6\int_0^{2\pi}(1-\cos^22t)\,\mathrm dt$

$=\displaystyle3\int_0^{2\pi}(1-\cos4t)\,\mathrm dt=6\pi$

3 0

2 years ago

(please help me out )In a recent year, 33.1% of all registered doctors were female. If there were 46,600 female registered docto

Montano1993 [528]

Answer:

im not gonna lie cat i have no clue.

Step-by-step explanation:

4 0

2 years ago

Read 2 more answers

I need help please either discord me the answer at F4deG0d#0988 or do it on here cause this is important.

algol13

Answer:

x= 12.5

So

2x = 25

4x = 50

6x = 75

Step-by-step explanation:

line CG is 180 degrees, so 12x + 30 = 180

x = 12.5

7 0

2 years ago

Find the area of each semicircle. Round to the nearest tenth. Use 3.14 for Pi.

pentagon [3]

Answer:

1. 69.4 / 2 = 34.7

2. 38.5 / 2 = 19.25

3. 201.1 / 2 = 100.55

I got these by caculating the area and dividing it by 2

4 0

2 years ago