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1 year ago

Use >, <, or = to solve the following problems below.

Mathematics

1 answer:

Elodia [21]1 year ago

3 0

(6^2)__>__(-6^2)

-5__=__ |-5|

0.372×1,000__<__37.2×100

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Which represents the solution(s) of the graphed system of equations, y = x2 – 2x and y = –2x – 1? (1, –1) (0, 0) and (0, –1) (0,

olganol [36]

ANSWER

No solution

EXPLANATION

The first equation is

$y = {x}^{2} - 2x$

and the second equation is

$y = - 2x - 1$

We equate the two equations to obtain;

${x}^{2} - 2x = - 2x - 1$

This implies that

${x}^{2} = - 2x + 2x - 1$

${x}^{2} = - 1$

There is no real number whose square is -1.

Therefore, the equation has no solution.

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2 years ago

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Solve: x + 1.5= 5.7<br> How do I solve this?

Mashutka [201]

Answer:

4.2

Step-by-step explanation:

5.7-1.5=4.2

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2 years ago

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What is the y-intercept of a line that has a slope of 1/4 and passes through point (8, 3)

sleet_krkn [62]

The y-intercept is 1

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3 years ago

The president of the student council wants to survey the student population about parking. She decides to take a random sample o

iren2701 [21]

Answer:

Should be (B)

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2 years ago

Write an equation that goes through (8,1) and is perpendicular to 2y + 4x =12

Serggg [28]

Answer:

2y -x + 6 = 0

Step-by-step explanation:

Here a equation and a point is given to us and we are interested in finding a equation which is perpendicular to the given equation and passes through the given point .

The given equation is ,

$\sf \longrightarrow 2y + 4x = 12 \\$

$\sf \longrightarrow 4x + 2y = 12$

Firstly convert this into slope intercept form , to find out the slope of the line.

$\sf \longrightarrow 2y = -4x +12\\$

$\sf \longrightarrow y =\dfrac{-4x+12}{2}\\$

$\sf \longrightarrow y =\dfrac{-4x}{2}+\dfrac{12}{2}\\$

$\sf \longrightarrow \red{ y = -2x + 6 }$

Now on comparing it to slope intercept form which is y = mx + c , we have ,

m = -2

And as we know that the product of slopes of two perpendicular lines is -1 . So the slope of the perpendicular line will be negative reciprocal of the slope of the given line. Therefore ,

$\sf \longrightarrow m_{\perp}=\dfrac{-1}{-2}=\red{\dfrac{1}{2}}$