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2 years ago

Use >, <, or = to solve the following problems below.

Mathematics

1 answer:

Elodia [21]2 years ago

3 0

(6^2)__>__(-6^2)

-5__=__ |-5|

0.372×1,000__<__37.2×100

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10 points!! Pls help with 5 and 6

marissa [1.9K]

Answer:

I only know number 5 so here it is

the solution for the left is: 2x6=12

the solution for the right is: 5x3+4x1=15+4=19

and the answers are: 1.12 . 2.19

5 0

2 years ago

The Fruit Juice Company sold 5,909,999,222 cans of juice last year. This

elixir [45]

A) 2000000000

5,909,999,222-3,999,002,135= 1,910,997,087 which is closest to answer A

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1 year ago

What are the best calculator apps besides Desmos to use for math

creativ13 [48]

Answer:

Math.way Algebra Calculator

Math.papa Algebra Calculator

Step-by-step explanation:

Im more of a "do it on a piece of paper" guy, but according to some comments, these are good sources.

If my answer is incorrect, pls correct me!

If you like my answer and explanation, mark me as brainliest!

-Chetan K

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2 years ago

PLEASE HELP!!! <br> BRAINLYEST!!!

11Alexandr11 [23.1K]

Answer:

Step-by-step explanation:

Using the rule of exponents

$\frac{a^{m} }{a^{n} }$ = $a^{(m-n)}$

Note that 8 = 2³, thus

$\frac{2^{5} }{8}$

= $\frac{2^{5} }{2^{3} }$

= $2^{(5-3)}$

= 2²

7 0

3 years ago

A training field is formed by joining a rectangle and two semicircles, as shown below. The rectangle is 96m long and 74m wide.

Oduvanchick [21]

Answer:

$11402.66 m^{2}$

Step-by-step explanation:

The width of rectangle is the diameter of the semi-circle part

Area of one semicircle is given by $\frac {0.5\pi d^{2}}{4}$

Total area of semi circle will be $2\times\frac {0.5\pi d^{2}}{4}$

Substituting 74 m for d and $\pi$ as 3.14 we obtain

Total area semi-circle= $2\times\frac {0.5*3.14\times 74^{2}}{4}=4298.66 m^{2}$

Area of rectangle is given by the product of length and width

Rectangular area= $96 m*74 m=7104 m^{2}$

Total area of rectangular and semi-circles will be

$4298.66 m^{2}+7104 m^{2}=11402.66 m^{2}$

Therefore, area of training field is $11402.66 m^{2}$

6 0

3 years ago