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3 years ago

Trignometry help what's the answer?

Mathematics

1 answer:

butalik [34]3 years ago

7 0

You have the 175 on the wrong line, the problem says 175 feet from the base, this is the bottom of the tree.

See attached picture for solution:

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Help need it…please I need it now

tino4ka555 [31]

Answer:

Here is the solution . see the attached file

4 0

3 years ago

The table shows the prices of 8 different treadmills at a sporting goods

irakobra [83]

Answer:

mean: $837.50; median: $810; mode: $810; range: $645

Step-by-step explanation:

Discounted prices are given as:

$640, $810, $755, $810, $1175, $900, $1080, $530

a. Mean = Sum of the Number of Term ÷ Total number of Terms

Total number of term = 8

Mean = ($640 + $810 + $755 + $810 + $1175 + $900 + $1080 + $530) ÷ 8

Mean = $837.50

b) Median.

$640, $810, $755, $810, $1175, $900, $1080, $530

The first step is to rearrange the discounted prices =

$530, $640, $755, $810, $810, $900, $1080, $1175

Second step is to find the number in the middle

$530, $640, $755, )$810, $810, ($900, $1080, $1175

= ($810 + $810) ÷ 2

= $1920 ÷ 2

= $810

Median = $810

c) Mode

This is calculated as the prices that occurs the most or more than once amongst the Discounted prices.

Discounted prices = $530, $640, $755, $810, $810, $900, $1080, $1175

Price that occurs more than once = $810.

Mode = $810

d. Range

This is calculate as the Highest Discounted price - Lowest Discounted price.

Highest Discounted price = $1175

Lowest Discounted price =$530

Range = $1175 - $530

= $645

6 0

3 years ago

A student claims that 3√80 is in the simplest radical form. Which statement is true?

nignag [31]

The answer i think is C

4 0

3 years ago

El maestro de matemáticas mostró una figura cuya área está representada por la siguiente expresión x² - 5x 6 = 0. ¿Cuánto miden

Mama L [17]

Answer:

x≈5

Step-by-step explanation:

x^2-5x6=0

x^2-30=0

x^2-30+30=30+0

x^2=30

x≈5

3 0

3 years ago

I don't understand how to construct a locus<br>pls explain, i need it

Harrizon [31]

1. Drawn a straight line AB =7 cm with the help of ruler.

2. With the help of compass drawn an arc from A and at the point where it cuts AB from that point made another arc drawn an arc cutting the previous arc.

3. From A drawn a straight line joining the arc and extend it to M.

4. With the help of ruler measured 5 cm and mark it as AC.

5. Joined BC and we get the required triangle.

6. From C drawn an arc and make it cut on AC and BC and from the point it cuts AC and BC drawn arc cutting each other and extend a line from point C extend a line to the point point of intersection of two arc.

7. Similarly we do for A and the point where the two line intersect denoted as O.

8. Made a perpendicular from O on AB this perpendicular will be radius and taking O as centre we draw a circle this is our incircle.

9. And AN is our locus of points equidistant from two lines AB and AC.

We need to construct a circle inscribed in triangle that is incircle it can be done by making angle bisector of two sides the point where it intersect will be incentre. The centre of required circle.

The angle bisector is the locus where points are equidistant from two sides.

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3 0

2 years ago