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Eddi Din [679]
3 years ago
8

Which expression is equivalent to log Subscript 3 Baseline StartFraction c Over 9 EndFraction?

Mathematics
2 answers:
statuscvo [17]3 years ago
5 0

Answer:

the 4th one

Step-by-step explanation:

mart [117]3 years ago
3 0

the answer is D.

Step-by-step explanation:

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Whatnis the gcf of 27 and 18
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The GCF of 27 and 18 would be 9. It is the largest or greatest common factor that can be evenly divided by in both the numbers 27 and 18.
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2565000

Step-by-step explanation:

Easy, multiply them in a table.

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Can someone explain this step by step for me? its from a review so ignore my wrong answer. Thank you!
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Answer:

P(\text{Male}|\text{Divorced})\approx0.092

Step-by-step explanation:

\displaystyle P(\text{Male}|\text{Divorced})=\frac{P(\text{Male and Divorced})}{P(\text{Male})}=\frac{\frac{9.6}{214.7}}{\frac{104.5}{214.7}}\approx0.092

We can even break this down further by simply only looking at the total amount of males, and finding the proportion of males that are divorced, which is \frac{9.6}{104.5}\approx0.092, the same value.

Note that P(Male | Divorced) means the probability of choosing a male, given (|) that person is divorced.

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2 years ago
Dimitri's table top is a whole number of
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3 years ago
The weights of five grapefruits are 7 47 ounces, 7.23 ounces, 6.46 ounces, 7.48 ounces, and 6.81 ounces. Using the
gulaghasi [49]

Answer:

<u>The approximate total weight of the grapefruits, using the clustering estimation technique is B. 35 ounces.</u>

Step-by-step explanation:

We notice that the weights of the grapefruits given are slightly down or above 7, then we will use <em>7 as our cluster</em> for the estimation, as follows:

Weights

7.47 ⇒ 7

7.23  ⇒ 7

6.46  ⇒ 7

7.48  ⇒ 7

6.81  ⇒ 7

<u>Now we can add up 7 + 7 + 7 + 7 + 7 for the weights of the grapefruits and the approximate total weight is B. 35 ounces.</u>

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3 years ago
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