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3 years ago

Which expression is equivalent to log Subscript 3 Baseline StartFraction c Over 9 EndFraction?

Mathematics

2 answers:

statuscvo [17]3 years ago

5 0

Answer:

the 4th one

Step-by-step explanation:

mart [117]3 years ago

3 0

the answer is D.

Step-by-step explanation:

You might be interested in

Find the distance between (1, 4) and (-2, 0)

Vanyuwa [196]

Answer:

$\boxed {d = 5}$

Step-by-step explanation:

Use the <u>Distance Formula</u> to help you determine the distance between two given points:

$d = \sqrt{(x_{2} - x_{1})^{2} + (y_{2} - y_{1})^{2}}$

First point: $(x_{1}, y_{1})$

Second Point: $(x_{2}, y_{2})$

-Apply the two given points onto the formula:

First point: $(1, 4)$

Second point: $(-2, 0)$

$d = \sqrt{(-2 - 1)^{2} + (0 - 4)^{2}}$

-Solve for the distance:

$d = \sqrt{(-2 - 1)^{2} + (0 - 4)^{2}}$

$d = \sqrt{(-3)^{2} + (-4)^{2}}$

$d = \sqrt{9 + 16}$

$d = \sqrt{25}$

$\boxed {d = 5}$

Therefore, the distance is $5$ .

4 0

3 years ago

Write an equation in point-slope form for the line that passes through each point with the given slope (-1,-2) m= 3

Vedmedyk [2.9K]

Answer:

Step-by-step explanation:

The Point-Slope form of equation of a line with slope of "m" and passing through point (x₁, y₁) is: y - y₁ = m(x - x₁)

m = 3

x₁ = -1

y₁ = -2

Therefore the equation:

y - (-2) = 3(x - (-1))

7 0

3 years ago

According to the rules of significant figures 1.25*200=300<br> will give brainliest pls

charle [14.2K]

Answer:

It's false

Step-by-step explanation:

1.25*200=250 not 300.

6 0

3 years ago

CORRECT ANSWER=BRAINLIEST POINTS

viktelen [127]

X=10 Y=1.25; X=8 Y=1; X=6 Y=0.75; X=4 Y=0.5

4 0

3 years ago

Drag the tiles to the correct boxes to complete the pairs. Not all tiles will be used.

Katena32 [7]

Answer:

(a)

$5^{-3}=\frac{1}{125}$

(b)

$-5^{-3}=-\frac{1}{125}$

(c)

$(-5^{-3})^{-1}=-125$

(d)

$(-5^{-3})^{0}=1$

Step-by-step explanation:

(a)

$5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$5^{-3}=\frac{1}{5^3}$

$5^{-3}=\frac{1}{5\times 5\times 5}$

$5^{-3}=\frac{1}{125}$ ........Answer

(b)

$-5^{-3}$

we can use property of exponent

$a^{-n}=\frac{1}{a^n}$

we get

$-5^{-3}=-\frac{1}{5^3}$

$-5^{-3}=-\frac{1}{5\times 5\times 5}$

$-5^{-3}=-\frac{1}{125}$ ........Answer

(c)

$(-5^{-3})^{-1}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{-1}=(-5)^{-3\times -1}$

$(-5^{-3})^{-1}=(-5)^3$

$(-5^{-3})^{-1}=(-5)\times (-5)\times (-5)$

$(-5^{-3})^{-1}=-125$ ........Answer

(d)

$(-5^{-3})^{0}$

we can use property of exponent

$(a^{n})^m=a^{m\times n}$

we get

$(-5^{-3})^{0}=(-5)^{-3\times 0}$

$(-5^{-3})^{-1}=(-5)^0$

we can use property

$a^0=1$

$(-5^{-3})^{0}=1$ ........Answer

4 0

3 years ago