Complimentary angles will add up to 90 degrees
x + y = 90
x = 2y
2y + y = 90
3y = 90
y = 90/3
y = 30......this is one angle
x = 2y
x = 2(30)
x = 60.....this is ur other angle
and ur larger angle is 60 degrees
A) Angle A has to be congruent to Angle D
Answer:
Step-by-step explanation:
Average Temperatures Suppose the temperature (degrees F) in a river at a point x meters downstream from a factory that is discharging hot water into the river is given by
T(x) = 160-0.05x^2
a. [0, 10]
For x = 0
T(0) = 160 - 0.05 × 0^2
T(0) = 160
For x = 10
T(10) = 160 - 0.05 × 10^2
T(10) = 160 - 5 = 155
The average temperature
= (160 + 155)/2 = 157.5
b. [10, 40]
For x = 10
T(10) = 160 - 0.05 × 10^2
T(10) = 160 - 5 = 155
For x = 40
T(10) = 160 - 0.05 × 40^2
T(10) = 160 - 80 = 80
The average temperature
= (80 + 155)/2 = 117.5
c. [0, 40]
For x = 0
T(0) = 160 - 0.05 × 0^2
T(0) = 160
For x = 40
T(10) = 160 - 0.05 × 40^2
T(10) = 160 - 80 = 80
The average temperature
= (160 + 80)/2 = 120
Hello !
20= Twenty
200= two hundread
5,000= five thousand
50,000= fifty thousand
we always replace the numbers that comes after the value with 0's
Good luck
1.5 is greater than 0.75, so her brother ate more
