3 years ago

Welppoo plzzzzzzzzzzzzzz

Mathematics

2 answers:

crimeas [40]3 years ago

6 0

Percent increase=amount of increase/original amount

Percent Increase=50/200=0.25% which equals a 25% increase

QveST [7]3 years ago

4 0

Answer:

the things wont load whats the question?

Step-by-step explanation:

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atroni [7]

Let $f(x)=\sec^{-1}x$ . Then $\sec f(x)=x$ , and differentiating both sides with respect to $x$ gives

$(\sec f(x))'=\sec f(x)\tan f(x)\,f'(x)=1$
$f'(x)=\dfrac1{\sec f(x)\tan f(x)}$

Now, when $x=\sqrt2$ , you get

$(\sec^{-1})'(\sqrt2)=f'(\sqrt2)=\dfrac1{\sec\left(\sec^{-1}\sqrt2\right)\tan\left(\sec^{-1}\sqrt2\right)}$

You have $\sec^{-1}\sqrt2=\dfrac\pi4$ , so $\sec\left(\sec^{-1}\sqrt2\right)=\sqrt2$ and $\tan\left(\sec^{-1}\sqrt2\right)=1$ . So $(\sec^{-1})'(\sqrt2)=\dfrac1{\sqrt2\times1}=\dfrac1{\sqrt2}$

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GREYUIT [131]

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3 years ago

What are the zeros of (x-2)(x^-9)

Nostrana [21]

I suspect you may have slipped up as you copied the question. Exactly as you wrote it, it has a single zero, at x= 2 .

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3 years ago

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Alex17521 [72]

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