The equivalent expression of x^3 (x^2 + 5x + 7) is x^5 + 4x^4 + x^4 + 8x^3 - x^3
<h3>How to determine the equivalent expression?</h3>
The expression is given as:
x^3 (x^2 + 5x + 7)
Expand the expression
x^3 * x^2 + x^3 * 5x + x^3 * 7
Evaluate the product
x^5 + 5x^4 + 7x^3
Expand the expression
x^5 + 4x^4 + x^4 + 8x^3 - x^3
Hence, the equivalent expression of x^3 (x^2 + 5x + 7) is x^5 + 4x^4 + x^4 + 8x^3 - x^3
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Hi!
This question is worded a little funny, but i think in understand what it's asking. Forgive me if i'm wrong.
Place values in math are pretty self-explanatory. It's just asking you what place each number is in.
For example:
If you were to write the number 12, the 1 would be in the tens place and the 2 would be in the ones place.
When speaking about decimals, you pretty much just have to add the letters 'th' to the end of the place value, but instead of decreasing as the numbers grow smaller, you increase and the ones place doesn't exist.
So in this case:
With 249.637, 2 is in the hundreds place. 4 is in the tens place. 9 is in the ones place. 6 is in the tenths place. 7 is in the hundreths place. 3 is in the thousandths place.
Hope this helps :)
Answer:
A t-score of 1.701 should be used to find the 95% confidence interval for the population mean
Step-by-step explanation:
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 29 - 1 = 28
Now, we have to find a value of T, which is found looking at the t table, with 28 degrees of freedom(y-axis) and a confidence level of 0.95(
). So we have T = 1.701.
A t-score of 1.701 should be used to find the 95% confidence interval for the population mean
1200 as you would round it down to 100 a week so you would do 100x12
The population of the town in 10 years would be 29,937.
