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3 years ago

What is the negative angle that is coterminal with 120∘120∘. write your answers in radians?

1 answer:

8 0

To find a positive and a negative angle coterminal with a given angle, you can add and subtract 360°.

$120^o-360^o=-240^o=-\dfrac{240\pi}{180}=-\dfrac{4\pi}{3}$

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MZJNM = 103°. Find mZJNK 2 * 24 32 K M L

just olya [345]

Answer:

m<ZJNK=47°

Step-by-step explanation:

m<ZJNK=103°-24°-32°=47°

8 0

3 years ago

Mixed 3 liters 20% solutions with 2 liters 70% solution. What’s the final concentration,

Advocard [28]

Answer:

(3×20%+2×70%)/3+2=40%

Step-by-step explanation:

Assuming the potions are the same type or do mix then probably the concentration of the potion depends on the type of reaction they have to each other.

Yet we can average the percentage of the active ingredient by the principle mentioned above

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3 years ago

Read 2 more answers

Write the equation of the line in slope- intercept and point-slope form.

AnnZ [28]

Answer:

Step-by-step explanation:

As we move from the x-intercept (-2, 0) to the y-intercept (0, 4), x increases by 2 (this is the run) and y by 4 (this is the rise). Thus, the slope of this line is

m = rise/run = 4/2 = 2.

Given the y-intercept (0, 4) and the slope (2), the slope-intercept form of the equation of this line is y = 2x + 4.

From this we get the point-slope form:

y = 2x + 4 becomes y - 4 = 2(x - 0), or just y - 4 = 2x.

3 0

3 years ago

The bar graph shows the number of school days Jalen had homework and did not have homework during the first six months of

Oksanka [162]

Given:

In July:

Number of days he has done the homework = 6

Number of days he has not done the homework = 4

In August:

Number of days he has done the homework = 16

Number of days he has not done the homework = 7

In September:

Number of days he has done the homework = 14

Number of days he has not done the homework = 4

In October:

Number of days he has done the homework = 14

Number of days he has not done the homework = 8

In November:

Number of days he has done the homework = 16

Number of days he has not done the homework = 4

In December:

Number of days he has done the homework = 5

Number of days he has not done the homework = 10

To find the months in which the difference between the number of days with homework and with no homework greater than 6.

Now,

In July,

The difference between the number of days with homework and with no homework = 6-4 = 2

In August,

The difference between the number of days with homework and with no homework = 16-7 = 9

In September,

The difference between the number of days with homework and with no homework = 14-4 = 10

In October,

The difference between the number of days with homework and with no homework = 14-8 = 6

In November,

The difference between the number of days with homework and with no homework = 16-4 = 12

In December,

The difference between the number of days with homework and with no homework = 10-5 = 5

Hence,

In 3 months the difference between the number of days with homework and with no homework greater than 6 and these are: August, September, November.

4 0

3 years ago

F(x)=3x^2-4 and g(x)=x+2 find f-g (x)

ratelena [41]

Answer:

Step-by-step explanation:

Here we subtract g(x)=x+2 from f(x)=3x^2-4

Properly labeled, we get:

(f - g)(x) = 3x^2-4 - (x+2) (Use of parentheses is essential here.)

(f - g)(x) = 3x^2 - x - 2

3 0

4 years ago