Answer:
Work done in stretching the spring = 7.56 lb-ft.
Step-by-step explanation:
Normal length of the spring = 8 in or 
ft
= 
ft
If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in
= 
ft
Force applied to stretch the spring = 12 lb
By Hook's law,
F = kx [where k is the spring constant and x = length by which the spring is stretched]
12 = k()
k = 18
Work done (W) to stretch the spring by ft will be
W = 
= 
= ![18[\frac{x^{2}}{2}]^{\frac{11}{12}}_0](https://tex.z-dn.net/?f=18%5B%5Cfrac%7Bx%5E%7B2%7D%7D%7B2%7D%5D%5E%7B%5Cfrac%7B11%7D%7B12%7D%7D_0)
= 9()²
= 7.56 lb-ft
Answer:
it is 6/2
Step-by-step explanation:
i just know it
Answer:
65,81,97,113,129
Step-by-step explanation:
she has 65 water bottles and she is buying boxes of water bottles (x) that hold 16 water bottles each. She can only buy up to 5 water bottles.
f(x) = 16x + 65...where f(x) = total water bottles and x = number of boxes
x < = 5 here is ur restriction
the range is ur f(x) values which represent the total number of water bottles...keep in mind, she can only buy 5. Therefore, the numbers that can be subbing in for x are 0 thru 5.
So when subbing in 0 thru 5 for x, the results for f(x) are :
{ 65,81,97,113,129 }
Answer:
51/10, 4 and 1/9, 5.116, and 5.98
Step-by-step explanation:
least to greatest
Answer:
Rectangle.
Round.
Arched.
Novelty.
Square.
Oval.
Octagon.
Sunburst.
Hope this is what you're looking for :)
Brainliest please
