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Bingel [31]
3 years ago
9

Can I get some help with this

Mathematics
1 answer:
Arturiano [62]3 years ago
6 0
I think it would be 4.7A - C
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2/3n=4n-10/3n-1/2 <br>can you show me how to do it step by step please
aleksklad [387]

Sorry IDk............    


4 0
3 years ago
The amount of radioactive uranium changes with time. The abscissas and ordinates of the points given are the time and amoung of
kakasveta [241]
The answer is <span>A. f(t) = 100(0.25)t
</span>
This may be solved by inserting all points to your answer and sseeing if they work. Since <span>A. f(t) = 100(0.25)t fits with all points, this best represents the relationship between f(t) and t.
</span>

Thank you for posting your question. I hope you found what you were after. Please feel free to ask me more.

 

 

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4 0
3 years ago
I need help omg thanks !
coldgirl [10]

Answer:

<em>Option C.</em>

Step-by-step explanation:

If you subtract each value from the next one, you see the differences are different. Therefore, it is not linear. Now divide each value by the previous value. You get 1.7 each time.

Answer: Option C.

6 0
3 years ago
In the figure, AA′ = 33 m and BC = 7.5 m. The span is divided into six equal parts at E, G, C, I, and K. Find the length of A′B.
Umnica [9.8K]
The correct answer for the question that is being presented above is this one: "18.12."
The image of this triangle is an isosceles triangle<span> with the base being 33 m (from angle A to angle A') and the right leg is 7.5 m long (BC) the span or width of the triangle is divided by 6 vertical lines with equal distances from each other. so we need to find the length of the left leg AB.</span>
4 0
3 years ago
What is the length of the hypotenuse of the triangle below?​
Vedmedyk [2.9K]

Answer:

Step-by-step explanation:

So here we have a 45-45-90 triangle.

This a special right triangle were the sides across from the 45 degree angles can be considered x, while the hypotenuse is two square roots of x.

Here since we have the sides across from the 45 degree angle we can conclude that x = 9\sqrt{2}

So if we wanted the hypotenuse we would just plug in this value of x like so:

hyp = x\sqrt{2} \\

hyp = (9\sqrt{2})(\sqrt{2})

hyp = 9(2)\\

hyp = 18

Therefore the hypotenuse is 18.

3 0
3 years ago
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