What is the mean for 87,93,86,90,84
2 answers:
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Answer:
The correct option is (c) 13.277.
Step-by-step explanation:
The observed data is:
Location Observed sales (units)
Northside 70
Pleasant Township 75
Southwick 70
I-90 50
Venice Avenue 35
TOTAL 300
The test statistic for the Goodness of fit test is:
For <em>k</em> independent samples this test statistic follows a Chi-square distribution with degrees of freedom (<em>k</em> - 1).
The sample size in this case is, <em>k</em> = 5.
The degrees of freedom is, (<em>k</em> - 1) = 4.
The level of significance is, <em>α</em> = 0.01.
The critical value of the test is:
**Use the Chi-square table.
Thus, the critical value is 13.277.
Answer:
And we can find this probability with the following difference:
We can use the following commands on the ti 84
2nd>VARS>DISTR
And then we look for normalcdf and we input this:
normalcdf(0.7,1.4,0,1)
The other possible code would be:
normalcdf(-1000,1,4,0,1)-normalcdf(-1000,0.7,0,1)
And we got:
Step-by-step explanation:
Previous concepts
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".
Solution to the problem
For this case we want to find this probability:
And we can find this probability with the following difference:
We can use the following commands on the ti 84
2nd>VARS>DISTR
And then we look for normalcdf and we input this:
normalcdf(0.7,1.4,0,1)
The other possible code would be:
normalcdf(-1000,1,4,0,1)-normalcdf(-1000,0.7,0,1)
And we got: