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VLD [36.1K]
3 years ago
14

A 3-column table with 6 rows. Column 1 is labeled Month with entries July, August, September, October, November, December. Colum

n 2 is labeled New with entries 35, 45, 20, 27, 51, 38. Column 2 is labeled Used with entries 62, 42, 55, 39, 12, 87.
Which type of car had the largest range in monthly sales? Explain how you came up with your answer.
Mathematics
2 answers:
Orlov [11]3 years ago
6 0

Answer:

I subtracted the highest and lowest numbers. The range for new cars was 31. The range for old cars was 75. The range for used cars was much bigger.

Hope's this helps you.

rodikova [14]3 years ago
4 0

Answer:

Lower quartile: 36

Upper quartile: 62

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At a cherry farm, the cost per pound of cherries depends on the amount of cherries bought. For an amount up to 100 pounds, the c
Leya [2.2K]

Answer:

they would have saved 35 dollars

Step-by-step explanation:

Ralph on his own would have paid  105 and jeff 140 but together with the discount they could save $35 by paying 210 in total with the discount.

3 0
3 years ago
A salesperson obtained a systematic sample of size 25 from a list of 500 clients. To do​ so, he randomly selected a number from
dangina [55]

Answer: Option 'D' is correct.

Step-by-step explanation:

Since we have given that

First term = 13

Increase each time = 20

Number of clients = 25

So, it forms an arithmetic progression:

So, 25 th term would be

a_{25}=a+(n-1)d\\\\a_{25}=13+(25-1)\times 20\\\\a_{25}=13+24\times 20\\\\a_{25}=13+480\\\\a_{25}=493

Hence, list would look like 13,33,............493.

Therefore, Option 'D' is correct.

3 0
3 years ago
What number raise power 3 is 729
hram777 [196]
3^x = 729
log(3^x) = log(729)
xlog(3) = log(729)
x = log(729)/log(3)
x = 6
5 0
3 years ago
30 POINTS!!!
vaieri [72.5K]

Answer:

jamal is a legend because he knows too much

6 0
2 years ago
Read 2 more answers
If a=2, b=3 and c=4 then find the numerical value of a2+2abc+b2+c2<br>​
qaws [65]

a=2 b=3 and c=4. then,

<em>a2+2abc+b2+c2</em>

<em>a2+2abc+b2+c2</em><em>=</em><em> </em><em>2</em><em>^</em><em>2</em><em>+</em><em>2</em><em>×</em><em>2</em><em>×</em><em>3</em><em>×</em><em>4</em><em>+</em><em>3</em><em>^</em><em>2</em><em>+</em><em>4</em><em>^</em><em>2</em>

<em>(</em><em>replace</em><em> </em><em>value</em><em> </em><em>of</em><em> </em><em>a</em><em>,</em><em> </em><em>b</em><em>,</em><em> </em><em>c</em><em> </em><em>by</em><em>2</em><em>,</em><em>3</em><em>,</em><em>4</em><em> </em><em>respectively</em><em> </em><em>tgen</em><em> </em><em>solve</em><em>)</em>

<em>=</em><em> </em><em>4</em><em>+</em><em>4</em><em>8</em><em>+</em><em>9</em><em>+</em><em>1</em><em>6</em>

<em>=</em><em> </em><em>7</em><em>7</em><em>…</em><em>…</em><em>…</em><em>…</em><em>…</em><em>…</em>

<em> </em><em>Therefore</em><em>,</em><em> </em><em>7</em><em>7</em><em> </em><em>is</em><em> </em><em>correct</em><em> </em><em>answer</em><em>.</em>

7 0
3 years ago
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