45 or below?? is there suppose to be a speed that she is driving
<span> I am assuming you want to prove:
csc(x)/[1 - cos(x)] = [1 + cos(x)]/sin^3(x).
</span>
<span>If we multiply the LHS by [1 + cos(x)]/[1 + cos(x)], we get:
LHS = csc(x)/[1 - cos(x)]
= {csc(x)[1 + cos(x)]/{[1 + cos(x)][1 - cos(x)]}
= {csc(x)[1 + cos(x)]}/[1 - cos^2(x)], via difference of squares
= {csc(x)[1 + cos(x)]}/sin^2(x), since sin^2(x) = 1 - cos^2(x).
</span>
<span>Then, since csc(x) = 1/sin(x):
LHS = {csc(x)[1 + cos(x)]}/sin^2(x)
= {[1 + cos(x)]/sin(x)}/sin^2(x)
= [1 + cos(x)]/sin^3(x)
= RHS.
</span>
<span>I hope this helps! </span>
Answer:
X Company charges 
more than Company Y
Step-by-step explanation:
Given:
Cost of X company = 
Cost of Y Company =
for n minutes
Cost of X company for n minutes = 
Cost of Y Company for n minutes =
Difference for n minutes we get by Subtracting Cost of Y Company for n minutes by Cost of X company for n minutes
Difference for n minutes = 
=
X Company charges more than Company Y
Answer: First, you identify how many rises and runs the line is from each point on a graph (intersection). Then you take the y's and the x's and do y2-y1/x2-x1 to get the slope!
<h3>
Answer: x*a^2 or a^2*x</h3>
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Work Shown:
a^(b+2) = a^b*a^2 ... break up the exponent
a^(b+2) = x*a^2 ... replace a^b with x
We don't know the value of 'a' nor the value of x, so we cannot evaluate further. This is the same as a^2*x because order of multiplication does not matter. For example, 2*3 = 6 and 3*2 = 6, so 2*3 = 3*2.
